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3 years ago

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Which of the following are true statements about any regular polygon? Check all that apply. A. all of it's angles measure 90 deg

rees B. It is a closed figure. C. It is a hexagon. D. It is a quardillateral. E. All of its angles have equal measures. F. Its sides are congruent line segments.

1 answer:

dmitriy555 [2]3 years ago

7 0

Answer:

B,E,F

Step-by-step explanation:

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The expression 6+16k factored using the GCF is what???????

tatiyna

Answer:

2(3 + 8k)

Step-by-step explanation:

given : 6+16k

note that the GCF of 6 and 16 is 2, hence we can factor 2 out of the expression

6+16k

= (2)(3) + (2)(8k)

= 2(3 + 8k)

4 0

3 years ago

Last year, Mark was 46 inches tall. This year, Mark’s height is 3 inches less than Peter’s height. Peter is 51 inches tall. How

Karolina [17]

48 inches tall hope this helps :)

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3 years ago

3/4 + -3/8 + -1/4=?<br> Evaluate the expression

Ann [662]

Answer: -1/8

Step-by-step explanation:

3/4 + -3/8 + -1/4

Find the LCM of 4, 8, and 4

That's 8 so you make an equivalent fraction for all fractions so the denominator is 8.

3/4 = 6/8

-3/8 = -3/8

-1/4 = -4/8

Now the expression looks like this:

6/8 + - 3/8 + -4/8

6/8 - 3/8 - 4/8

6/8 - 7/8

-1/8

Hope that helped!

8 0

3 years ago

What is the perimeter of the triangle shown on the coordinate plane,to the nearest tenth of a unit ?

ollegr [7]

Answer:

25.6 units

Step-by-step explanation:

From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

$d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}$

where

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

- For AB:

$d=\sqrt{[1-(-5)]^{2}+(4-4)^2}$

$d=\sqrt{(1+5)^{2}+(0)^2}$

$d=\sqrt{(6)^{2}}$

$d=6$

- For BC:

$d=\sqrt{(3-1)^{2} +(-4-4)^{2}}$

$d=\sqrt{(2)^{2} +(-8)^{2}}$

$d=\sqrt{4+64}$

$d=\sqrt{68}$

$d=8.24$

- For AC:

$d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}$

$d=\sqrt{(3+5)^{2} +(-8)^{2}}$

$d=\sqrt{(8)^{2} +64}$

$d=\sqrt{64+64}$

$d=\sqrt{128}$

$d=11.31$

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

$p=AB+BC+AC$

$p=6+8.24+11.31$

$p=25.55$

$p=25.6$

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

6 0

3 years ago

Which is a graph for the inequality m < -2 ?

aliya0001 [1]

Answer:

B

Step-by-step explanation:

This answer shows values of -2, and less than -2

6 0

3 years ago