3 years ago

An elephants heart beats 28 times per minute.How many times does it beat in a half an hour?

Mathematics

1 answer:

Bumek [7]3 years ago

7 0

30 x 28= 840

It's would beat 840 times in half an hour.

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Please answer this ( 10 points) -10 + 2d =8 What is D?

coldgirl [10]

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3 years ago

The area of a hall is 806 sq. ft. Its length is 5 ft greater than its width. Find the dimensions of the hall. Enter the results

BartSMP [9]

Answer:

width is = 26ft

length is = 31ft

Step-by-step explanation:

The area of hall is 806 sq. ft.

length is 5 ft greater than its width.

L = 5+b

L*b = 806

(5+b)*b= 806

5b +b² = 806

B²+5B-806= 0

Solving quadratically

B² +31B -26B -806= 0

B(B+31)-26(B+31)= 0

(B-26)(B+31)= 0

B= 26 or -31

So the value of the width must be positive so the width is = 26ft

If width is 26, length is 26+5 = 31ft

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3 years ago

What is an equation for the line that passes through points (8, -3) and (9, 10)

34kurt

Answer:

y=13x-107

Step-by-step explanation:

(10- -3)/(9-8)=13

10=13*9+b

b=10-117=-107

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3 years ago

Which one is repeating decimal 0.7777777 4.252525 0.123123 1.111114

Bas_tet [7]

The first one 0.7777777

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3 years ago

Read 2 more answers

Element X decays radioactively with a half life of 9 minutes. If there are 610grams of

Nookie1986 [14]

A half-life of 9 minutes corresponds to a decay factor k such that

$\dfrac12=e^{9k}\implies k=-\dfrac19\ln\left(\dfrac12\right)$

Then the time it takes for the substance to decay from 610 g to 124 g is time t such that

$124\,\mathrm g=(610\,\mathrm g)e^{kt}$

Solve for t :

$\dfrac{62}{305}=e^{kt}$

$\ln\left(\dfrac{62}{305}\right)=kt$

$t=\dfrac1k\ln\left(\dfrac{62}{305}\right)\approx20.686$

so it takes about 20.7 min for the 610 g sample to decay down to 124 g.

4 0

3 years ago