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Sergeeva-Olga [200]
3 years ago
13

What is the slope of the line passing through the point 3,5 and -1,7

Mathematics
1 answer:
creativ13 [48]3 years ago
5 0

Answer:

m = -1/2

Step-by-step explanation:

As we move from the point (-1, 7) to the point (3, 5), x increases by 4 (this is the "run") and y decreases by 2 (this is the "rise").

Thus, the slope of the line connecting these two points is

m = rise / run = -2/4, or m = -1/2.

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there are 8 students on the minibus. five of the students are boys. what fraction of the students or boys?
Hunter-Best [27]

Answer: 5/8


Explanation:

total = 8

boys = 5

fraction = 5/8

3 0
3 years ago
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PLEASE HELP ME YOU GET IT RIGHT I WILL MARK BRAINLIST but if its wrong... i report you
mamaluj [8]
I’m pretty sure it’s 60 but I’m not 100% sure so I’m sorry if it’s wrong
6 0
2 years ago
Only answer if yk it please! correct answer will get brainliest!
DanielleElmas [232]

Answer:

so x = 4 and x = -2/3

Step-by-step explanation:

Solve for x using the Master Product:

3x^2-10x-8=0

we see   3*(-8) = -24   and  2 * (-12) = -24   and  2 + -12 = -10

so   3x^2  + 2x  -  12x  - 8 = 0

x (3x + 2) -4 (3x + 2) = 0

(x - 4)(3x + 2) = 0

so x = 4 and x = -2/3

7 0
3 years ago
1/2 + 1/4 = how many quarters
Aleksandr [31]

Answer:

3

Step-by-step explanation:

1/2 = 0.5

1/4 = 0.25

1/2 + 1/4

= 0.5 + 0.25

= 0.75

= 75/100

= 3/4

Quarter is 1/4.

3/4 can be written as 3 x 1/4

Hence,

1/2 + 1/4 is 3 times 1/4

1/2 + 1/4 = 3 quarters.

5 0
1 year ago
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Shayla has 6 1/2 pounds of potato salad into containers each of which holds 1 5/8 pounds. How many containers does she need?
Oksi-84 [34.3K]

let's firstly convert the mixed fractions to improper fractions and then divide.

\bf \stackrel{mixed}{6\frac{1}{2}}\implies \cfrac{6\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{13}{2}}~\hfill \stackrel{mixed}{1\frac{5}{8}\implies \cfrac{1\cdot 8+5}{8}}\implies \stackrel{improper}{\cfrac{13}{8}} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{total salad}}{\cfrac{13}{2}}\div \stackrel{\stackrel{\textit{conainer's}}{\textit{capacity}}}{\cfrac{13}{8}}\implies \cfrac{\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\underset{1}{\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}\cdot \cfrac{\stackrel{4}{\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}{\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies 4

6 0
3 years ago
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