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Yuki888 [10]
3 years ago
12

Anyone have the answer to this question? Thanks

Mathematics
1 answer:
jolli1 [7]3 years ago
7 0
Sorry I’m too lazy but since no one is answering. You can put these into an online calculator or the internet to find your answers that equal to the one in the question.
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What logarithmic function represents the data in the table? x f(x) 25 2 125 3 625 4
Ray Of Light [21]
\bf recall\\\\
log_{{  a}}{{  b}}=y \iff {{  a}}^y={{  b}}\qquad\qquad 
{{  a}}^y={{  b}}\iff log_{{  a}}{{  b}}=y \\\\
-----------------------------\\\\
thus\qquad 
\begin{array}{cc|llll}
x&y&5^y=x\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
25&2&5^2=25\\
125&3&5^3=125\\
625&4&5^4=625\\
\end{array}
\\\\\\
\textit{so hmmm what would that be in log notation? }\  5^y=x \iff \boxed{?}
6 0
3 years ago
Read 2 more answers
C=Wtc/1000 for W please I need help it's algebra
DedPeter [7]
C1000÷ct=w

you pretty much ×1000 and then ÷t and c
3 0
3 years ago
Solve for y:<br> x + 2y = -8<br><br> y=-1/2x+4<br> y=-1/2x-4<br> y=-2x - 4<br> y=1/2x-4
adelina 88 [10]

Answer:

x + 2y = -8 = y = -4 - 1/2x

y= -1/2x + 4 =  y = 4

y= -1/2x - 4 = y = -4

y=-2x - 4 = y = -4

y=1/2x-4 = y = -4

Step-by-step explanation:

(x + 2y = -8 = y = -4 - 1/2x)

x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\

4 0
3 years ago
Solve the system of equations: <br> X+y+z=5<br> -3x-4y+4z=15<br> 2x-y-4z=-8
atroni [7]

Answer:

  (x, y, z) = (3, -2, 4)

Step-by-step explanation:

The attachment shows a solution using a graphing calculator where the first equation is solved for z, and that expression is substituted into each of the other two equations. The solution to that system is (x, y) = (3, -2). Using these values in the expression for z, we find ...

  z = 5 -(3 +(-2)) = 4

The solution is (x, y, z) = (3, -2, 4).

__

Your graphing calculator and/or online tools can give you the reduced row echelon form of the augmented matrix representing the system:

  \left[\begin{array}{ccc|c}1&1&1&5\\-3&-4&4&15\\2&-1&-4&-8\end{array}\right]

__

If you're solving by hand, you can do the substitution described above to eliminate z from one equation. You can eliminate z from another equation by adding the last two:

  -3x -4y +4(5 -x -y) = 15   ⇒   -7x -8y = -5

  (-3x -4y +4z) +(2x -y -4z) = (15) +(-8)   ⇒   -x -5y = 7

This pair of equations can be solved for x and y in any of the usual ways. Using the second equation to substitute for x, for example, gives you ...

  -7(-5y -7) -8y = -5   ⇒   27y = -54   ⇒   y = -2

  x = -5(-2) -7 = 3

  z = 5 -(3) -(-2) = 4

_____

<em>Additional comment</em>

If all that is needed is a solution, we prefer a graphical or matrix approach. These take about the same amount of time. Both require a little additional effort to determine exact values when the solutions are not integers.

6 0
2 years ago
To increase an amount by 7%, what single multiplier would you use ?
Scrat [10]
You would use 1.07 for that
6 0
3 years ago
Read 2 more answers
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