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EleoNora [17]
3 years ago
12

In triangle MNP, medians NQ and PR intersect at S. If PS = 8 and QS = 3 then which of the following is the value of NQ + PR

Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

(2) 22

Step-by-step explanation:

In the given triangle MNP, the medians are straight lines drawn from the angle to opposite side so as to divide the side into equal parts.

PS = 8 and QS = 3, thus;

PS = NS = 8 (congruent property of ΔRSN and ΔQSP)

QS = SP = 3 (congruence property)

So that,

NQ = NS + SQ

     = 8 + 3

    = 11

PR = PS + SR

    = 8 + 3

   = 11

Thus;

NQ + PR = 11 + 11

             = 22

Therefore, NQ + PR = 22

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koban [17]
Hi there!

-  \frac{1}{3}  + 4 +  \frac{2}{3}  =
First we rearrange the sum in order to add both of the fractions first. We can rearrange because the only thing we need to do is adding.

-  \frac{1}{3}  +  \frac{2}{3}  + 4 =
Add the fractions.
** If you don't get this, think of this story: you lack 1/3 of an apple pie and someone gives you 2/3 of pie. How much pie do you have left?
- 1 / 3 + 2 / 3 = 1 / 3 **

\frac{1}{3}  + 4 =
Finally add 4 to our found fraction.

\boxed{ 4\frac{1}{3} }
Therefore, the answer is 4 1/3.

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3 years ago
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3 years ago
A researcher was testing the number of popcorn kernels that popped out of a mini bag of 100 kernels after being cooked for the s
Lelechka [254]

Answer:

The percentage of the bag that should have popped 96 kernels or more is 2.1%.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.

The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.

Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.

Compute the probability that a bag popped 96 kernels or more as follows:

Apply continuity correction:

P( X\geq 96)=P( X>96+0.50)

                 =P( X>96.50)\\=P(\frac{X-\mu}{\sigma}>\frac{96.50-72}{12})\\=P(Z>2.04)\\=1-P(Z

*Use a <em>z</em>-table.

The probability that a bag popped 96 kernels or more is 0.021.

The percentage is, 0.021 × 100 = 2.1%.

Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.

3 0
3 years ago
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jekas [21]

Answer:

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Step-by-step explanation:

(170+30)-41=170+(30-41)

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2 years ago
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