Which expression represents, five times the quotient of two numbers?

hichkok12 [17]

Answer and Step-by-step explanation:

$We~ need ~to ~find ~the~ HCF~ of ~1624, 522 ~and~ 1276~so~in~order~to~find~this$ $we~will~have~to~use~prime~factorization.$

<u><em>→ Prime factorization of 1624 is :</em></u>

= 2 × 2 × 2 × 7 × 29

<u><em>→ Prime factorisation of 522 is :</em></u><em> </em>

= 2 × 3 × 3 × 29

<u><em>→ Prime factorisation of 1276 is :</em></u><em> </em>

= 2 × 2 × 29 × 11

→ $HCF~of~1624 , 522 , 1276~is:$ <em> </em> $=2$ × $29=58$

8 0

4 years ago

Read 2 more answers

WILLGIVEBRAINLIEST,THANKS,5STARS!<br> PLEASE HELP!<br> PLEASE EXPLAIN IN DEPTH!

bearhunter [10]

<h3>Answer:</h3>

x=2

<h3>Solution:</h3>

In order to isolate x, we should first of all take the square root of both sides.
If we take the square root of the left-hand side, we will get
$x-\displaystyle\frac{1}{2}$
How about the right-hand side? Well, we should take the square root of the numerator (9) and the denominator (4)
So we have
$x-\displaystyle\frac{1}{2} =\frac{3}{2}}$
Move -1/2 to the right:
$x=-\displaystyle\frac{3}{2} +\frac{1}{2}$
$x=\displaystyle\frac{4}{2}$
x=2

Hope it helps.

Do comment if you have any query.

6 0

2 years ago

Find sin X, sin Z, cos X, and cos Z. Write each answer as a simplified fraction.

just olya [345]

Answer:

Find the answers below

Step-by-step explanation:

Using m<X as the reference angle

Opposite YZ = 7

Adjacent XY = 10

Hypotenuse XZ = √149

Using the SOH CAH TOA identity

sinX = opp/hyp

sinX =YZ/XZ

sinX = 7/√149

For cos X

cos X = adj/hyp

cos X =10/√149

Using m<Z as reference angle;

Opposite XY = 10

Adjacent YZ = 7

Hypotenuse XZ = √149

Using the SOH CAH TOA identity

sinZ = opp/hyp

sinZ =10/√149

sinZ = 7/√149

For cos Z

cosZ = 7/√149

7 0

3 years ago

What is 1,000 raised to the power of 5?

I am Lyosha [343]

The answer would be 5000.

6 0

3 years ago

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What is the probability that a five-card poker hand contains exactly one ace?.

spin [16.1K]

The probability of selecting exactly one ace is its likelihood

The probability that a five-card poker hand contains exactly one ace is 29.95%

<h3>How to determine the probability?</h3>

There are 4 aces in a standard deck of 52 cards.

The probability of selecting an ace would be:

p = 4/52

Also, there are 48 non-ace cards in the standard deck

So, the probability of selecting a non-ace after an ace has been selected is:

p = 48/51

The probability of selecting a non-ace up to the fifth selection are:

After two cards have been selected is: 47/50.
After three cards have been selected is: 46/49.
After four cards have been selected is: 45/48.

The required probability is then calculated as:

P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Where n is the number of cards i.e. 5

So, we have:

P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Evaluate

P(1 Ace) = 0.2995

Express as percentage

P(1 Ace) = 29.95%

Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%