Answer:
n¹³
Step-by-step explanation:
Division and multiplication have the same priority in pemdas, so you can solve this by dividing/multiplying from left to right.
Also remember that when dividing exponents of the same base, you subtract them, and when multiplying, you add them.
n⁶· n⁵ · n⁴ ÷ n³ · n² ÷ n
= (n⁶· n⁵) · n⁴ ÷ n³ · n² ÷ n
= (n¹¹ · n⁴) ÷ n³ · n² ÷ n
= (n¹⁵ ÷ n³) · n² ÷ n
= (n¹² · n²) ÷ n
= n¹⁴ ÷ n
= n¹³
Ultimately you just have to calculate
6 + 5 + 4 - 3 + 2 - 1 = 13
2a + 3b = 6
5a + 2b = 4
We multiply the first equation by 5 and the second by 2 and and subtract the second from the first:
10a + 15b = 30
-10a -4b = -8
11b = 22
b = 2
2a + 3(2) = 6
2a = 0
a = 0
Checking,
5(0) + 2(2) = 4
4 = 4, true
Answer:
2x+6y=-4
Step-by-step explanation:
Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
