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Charra [1.4K]
4 years ago
14

What is the range of y=csc(x)

Mathematics
2 answers:
NISA [10]4 years ago
7 0

The answer on e2020 is C.

soldier1979 [14.2K]4 years ago
3 0

Answer:

y \leq -1\text{ and }y \geq 1        

Step-by-step explanation:

We have to find the range of given function:

y = f(x) = cosec(x)

The attached image shows the graph for the given function.

The range is a set of all the possible values of the dependent variable or y to the corresponding possible x values.

The range of the given function is:

y \leq -1\text{ and }y \geq 1

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5(3X+2)

Step-by-step explanation:

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4 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 42 lik
Step2247 [10]

Answer:

Step-by-step explanation:

Universal set

U = 500

The number that likes snickers

n(S) = 42

The number that like Twix.

n(T) = 110

The number that like Reeses

n(R) = 125

n(S n T) = 33

n(T n R) = 62

n(S n R) = 26

n( S n R n T) = 22

Then,

n(S n T) only = n(S n T) - n(S n R n T)

n(S n T) only =33 - 22 = 11

n(T n R) only = n(T n R) - n(S n R n T)

n(T n R) only =62 - 22 = 40

n(S n R) only = n(S n R) - n(S n R n T)

n(S n R) only =26 - 22 = 4.

Also,

n(S) only = n(S) - n(S n R) - n(S n T) only

n(S) only = 42 - 26 - 11 = 5

n(T) only = n(T) - n(T n R) - n(T n S) only

n(T) only = 110 - 62 - 11 = 37

n(R) only = n(R) - n(S n R) - n(R n T) only

n(R) only = 124 - 26 - 40 = 58

Then, to know if some student don't like any of the of chocolate,

Let know the number of students that like the chocolate candy

n(S) + n(T)only + n(T n R)only + n(R) only

42 + 37 + 40 + 58 = 177 students.

Therefore, the total students that like chocolate candy is 177, so those  that does not like any of them are

n(S U R U T)' = U – n(S U R U T)

n(S U R U T) = 500 - 177 = 323.

So, the question is how many student likes at most 2 kinds of these chocolates, this means that they can like exactly 2 or less or even none.

So, this category are

n(2 most) = n(S n T)only + n(R n T)only + n(S n R)only + n(s)only + n(T)only + n(R)only + n(S U R U T)'

n(2 most) = 11 + 40 + 4 + 5 + 37 + 58 + 323

n(2 most) = 478

The correct answer is E.

Check attachment for Venn diagram

5 0
3 years ago
Could I possibly get help with this?
ad-work [718]

Answer:

? = 74.64111442

Step-by-step explanation:

\frac{sin(x)}{27}=\frac{sin(90)}{28}

       =\frac{1}{28}

        *27

        =\frac{27}{28}

sin^{-1}(27/28)

=74.64111442

5 0
3 years ago
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