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3 years ago

Write an equation for the line in the graph that passes through the points (0,4) and (12,16).

Mathematics

1 answer:

Inga [223]3 years ago

8 0

Answer:

We have,

y-y1=m(x-x1)

or,y-4=-1(x-0)

or,y-4=-x

or,x+y=4 is the required equation

Step-by-step explanation:

it it helps u ...plz mark it as brainliest

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Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)

tigry1 [53]

Answer:

$M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ . Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

$y=k\cdot x + b$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$k$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $b = 1$ , $x = 1$ and $y = 3$ , then we clear slope and solve the resulting expression:

$k = \frac{y-b}{x}$

$k = \frac{3-1}{1}$

$k = 2$

Then, we conclude that point $M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ , whose graph is presented below.

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Dennis_Churaev [7]

Answer: 2

Step-by-step explanation:

1. Convert the mixed numbers to improper fractions,

2. then find the LCD and combine.

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Step-by-step explanation:

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