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VikaD [51]
2 years ago
14

What is the product of these?

Mathematics
1 answer:
Phoenix [80]2 years ago
3 0
<h2><u>96√5</u></h2>

8 × 4 = 32

√3 ×√15 = √45

√75 = √9 × √5

√9 = 3

√75 = 3√5

32 × 3√5 = 96√5

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3 0
2 years ago
Describe the translation of the function from the parent function f(x) = x².
kkurt [141]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;&#10;\end{array}\\

\bf \begin{array}{llll}&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}&#10;

now, notice the template above... now let's see your function \bf y=x^2+4\implies &#10;\begin{array}{llllll}&#10;y=&1(&1x&+&0)^2+&4\\&#10;&A&B&&C&D&#10;\end{array}

so.. what do you think was the shift then?
8 0
3 years ago
How do you do this? I am really confused
german

Answer:

Step-by-step explanation:

ok, so this is an infinitly repeating function, so you can write it as:

sqrt(12-x)

Although, x is also equal to sqrt(12-x), so

x = sqrt(12-x), and

x^2 = 12-x

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now just apply the quadratic formula and you're good

hope i helped :D

8 0
1 year ago
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