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Viefleur [7K]
3 years ago
11

What is the value of x? -2/7x+6+1/7x=18 x=

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0
- \frac{2}{7} x + 6 + \frac{1}{7} x = 18

First, simplify \frac{2}{7} x to \frac{2x}{7} / Your problem should look like: -\frac{2x}{7} + 6 + \frac{1}{7} x = 18
Second, simplify \frac{1}{7} x to \frac{x}{7} / Your problem should look like: - \frac{2x}{7} + 6 + \frac{x}{7} = 18
Third, simplify - \frac{2x}{7} + 6 + \frac{x}{7} to - \frac{x}{7} + 6 / Your problem should look like: -\frac{x}{7} + 6 = 18
Fourth, regroup terms. / Your problem should look like: 6 - \frac{x}{7} = 18
Fifth, multiply both sides by 7. / Your problem should look like: 42 - x = 126
Sixth, subtract 42 from both sides. / Your problem should look like: -x = 126 - 42
Seventh, simplify 126 - 42 to 84. / Your problem should look like: -x = 84
Eighth, multiply both sides by -1. / Your problem should look like: x = -84

Answer: x = -84

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(10 points) Suppose you are rolling a fair die 600 times independently. Let X count the number of sixes that appear. (a) What ty
andrezito [222]

Answer:

let me think

Step-by-step explanation:

i want free points

7 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
Fine The slope of the line on the graph
Brrunno [24]

Take any 2 points through which the line on graph passes,

(0,-1) =(x₁,y₁)

& (2,-4)=(x₂,y₂)

slope=(y₂-y₁)/(x₂-x₁)

=[-4-(-1)]/(2-0)

=-3/2

3 0
3 years ago
Please answer 1 and 2 soon
olganol [36]

Answer:

1.36+3+(32)(2)

=57

error is that 6 is the wrong answer

4 0
3 years ago
Will mark brainliest if get the correct answer.
Savatey [412]

Answer:

Perimeter of rectangle before folded = 56 in

Total area after folding = 156 sq in

Step-by-step explanation:

Rectangle before folded:  l = 16 and w = 12

                                           P = 2(16) + 2(12) = 32 + 24 = 56 in.

Figure after folding:   Area of trapezoid + area of rectangle

Area of trapezoid = h(b_{1} + b_{2})/2 = 6(4 + 16)/2 = 60

Area of rectangle = lw = 16(6) = 96

Total area after folding = 60 + 96 = 156 sq in.

Note:  You could also find the area after folding by substracting the areas of the two triangles in the corners from the area of the original rectangle.  Your choice.  OK?

8 0
2 years ago
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