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Viefleur [7K]
3 years ago
11

What is the value of x? -2/7x+6+1/7x=18 x=

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0
- \frac{2}{7} x + 6 + \frac{1}{7} x = 18

First, simplify \frac{2}{7} x to \frac{2x}{7} / Your problem should look like: -\frac{2x}{7} + 6 + \frac{1}{7} x = 18
Second, simplify \frac{1}{7} x to \frac{x}{7} / Your problem should look like: - \frac{2x}{7} + 6 + \frac{x}{7} = 18
Third, simplify - \frac{2x}{7} + 6 + \frac{x}{7} to - \frac{x}{7} + 6 / Your problem should look like: -\frac{x}{7} + 6 = 18
Fourth, regroup terms. / Your problem should look like: 6 - \frac{x}{7} = 18
Fifth, multiply both sides by 7. / Your problem should look like: 42 - x = 126
Sixth, subtract 42 from both sides. / Your problem should look like: -x = 126 - 42
Seventh, simplify 126 - 42 to 84. / Your problem should look like: -x = 84
Eighth, multiply both sides by -1. / Your problem should look like: x = -84

Answer: x = -84

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maks197457 [2]

Answer: L, J, K

Step-by-step explanation:

L, J, and K are collinear because they all lie on the same line.

8 0
3 years ago
Which composition of transformations maps figure EFGH to figure E"F"G"H"?
Lostsunrise [7]

The  composition of transformations maps figure EFGH to figure E"F"G"H" is Option A.a reflection across line k followed by a translation down.

<h3>What is translation?</h3>

A translation can be explained as the movement of a shape in a direction which could be up, down but the appearance of the figure remain unchanged in any other way.

And from the figure, we can see that a translation is used, because of the movement of EFGH to figure E"F"G"H" which occurred in the same direction.

Hence,  composition of transformations maps figure EFGH to figure E"F"G"H" is Option A.a reflection across line k followed by a translation down.

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7 0
2 years ago
ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
  (5/8 -1/6 -1/12)AB·h = 30 cm²
  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
6 0
3 years ago
Convert 0.2194 to a fraction.<br>Give your answer in its simplest form.​
77julia77 [94]
2194/10000 using prime factorisation method
4 0
2 years ago
Read 2 more answers
Use the position equation given below, where s represents the height of the object (in feet),
mariarad [96]

The answers to the questions are

  • The mathematical model is given as s = −16t2 + 1054
  • The height after 4.5 seconds is 730 feet
  • the time it would take to strike the ground is 8.11 seconds.

<h3>How to solve for the position of the object</h3>

The mathematical model of this problem would be written as

s = −16t2 + v0t + s0

s0 = 1054

then we would have

s = −16t2 + 1054

b. after 4.5 seconds the height is going to be

s = −16t2 + 1054

=  −16(4.5)² + 1054

= -16 * 20.25 + 1054

= 730

C. the time that it takes to strike the ground

s = −16t² + 1054

= 16t² = 1054

t² = 1054/16

= 65.88

t = √65.88

t = 8.11

Hence the time it would take to strike the ground is 8.11 seconds.

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8 0
1 year ago
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