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Minchanka [31]
4 years ago
8

Solve the system of equations below by graphing both equations with a pencil and paper. What is the solution?

Mathematics
2 answers:
BlackZzzverrR [31]4 years ago
8 0

Answer: B. (2,1)

Step-by-step explanation:

The given system of equation :

y=2x-3...........................(1)\\\\y=-2x+5.............................(2)

Adding equation (1) and (2), we get

2y=-3+5\\\\\Rightarrow\ 2y=2\\\\\Rightarrow\ y=1

Substitute the value of y in the first equation , we get

1=2x-3\\\\\Rightarrow\ 2x=1+3\\\\\Rightarrow\ 2x=4\\\\\Rightarrow\ x=2

Therefore, the solution to the given system of equations = (2,1)

Nataly [62]4 years ago
7 0

Answer:

B    (2,1)

Step-by-step explanation:

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Drag the measurements to the containers to show equal length.
Pani-rosa [81]

The measurements that show equal length is 15 yd and 540 in, 195 ft and 2340 in, 5280 yd and 15840 ft

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

1 ft = 12 in; 1 yd = 3 ft and 1 yd = 36 in.

Hence:

15 yd = 15 yd * 36 in per yd = 540 in

195 ft = 195 ft * 12 in per ft = 2340 in

5280 yd = 5280 yd * 3 ft per yd = 15840 ft

The measurements that show equal length is 15 yd and 540 in, 195 ft and 2340 in, 5280 yd and 15840 ft

Find out more on equation at: brainly.com/question/2972832

3 0
2 years ago
Using what you know about right triangle trigonometry, salt the triangle round the side to the nearest 10th and angle measures t
Elden [556K]

Answer:

Angle A = 49°  Angle B = 41°  Side AB = 30.5

Step-by-step explanation:

Let's work out Angle A and Angle B first. We are given AC and CB, therefore AB must be the hypotenuse as it is the longest side.

AC and CB must be the opposite and adjacent sides, therefore we can use tan(x) = Opposite/Adjacent for working out both Angle A and Angle B.

Angle A:

tan(A) = 23/20  For Angle A, CB (23) is the side opposite the angle and AC (20) is the side in between Angle A and the right angle, also the adjacent side.

A = tan^{-1}(\frac{23}{20})  We do the inverse of tan here.

A = 48.9909131

A = 49°  Rounding to the nearest degree simply means to the nearest whole number.

Angle B:

tan(B) = 20/23  For Angle B, AC (20) is the side opposite the angle and CB (23) is the side in between Angle B and the right angle, also the adjacent side.

B = tan^{-1}(\frac{20}{23})

B = 41.0090869

B = 41°

Side AB:

We can just use Pythagoras' Theorem here to work out AB, but I will also use trigonometry to show you how you can use both formulas. When I use trigonometry, I will only be using Angle A as an example.

Pythagoras' Theorem: a^{2}  + b^{2}  = c^{2}

AC = 20 = a

CB = 23 = b

20^{2}  + 23^{2}  = c^{2}

929 = c^{2}

c = \sqrt{929}

c = 30.47950131

c = 30.5  Rounding to the nearest 10th simply means rounding to 1 decimal place.

Trigonometry: SOHCAHTOA

Angle A = 49°

AC = 20  I will use AC as our adjacent side instead of CB. They will both give us the same answer anyways.

AB will always be the hypotenuse in the given right-angled triangle.

cos(x) = Adjacent/Hypotenuse

cos(49) = 20/AB

ABcos(49) = 20  Here we multiply by AB, our hypotenuse.

AB = 20/cos(49)  Now we divide by cos(49)

AB = 30.48506173  As you can see here, this answer is different from the Pythagoras' Theorem one because we rounded our angle values, meaning out angle values aren't exact! Instead, use Pythagoras' Theorem here for more accurate results instead of Trigonometry.

AB = 30.5  They still give us the same answer in the end!

I hope this helps you!! ^-^

7 0
3 years ago
One number is 20 times another number. The product of the two numbers is 180. Write an equation and use it to find all pairs of
nadezda [96]
Y = 20x

y • x = 180

180/x = y

180/x = 20x

180 = 20x^2

x^2 = 6

x = + or - 3

Therefore y must equal + or - 60.
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3 years ago
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iVinArrow [24]
To fit the formula, b is the first term, -5, and c is the common ratio, or -2
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4 years ago
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Solve the system using any method.<br> 2.5x - 2.5y = 10<br> - 5x + 5y = - 15
AlexFokin [52]

Answer:

last option: No solution

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