Answer:
Number of calls expected in next week by manager = 7940
Average Number of calls that call center agent will attend in an hour =7 calls
It is also given that, Call center remain open for 10 hours 5 days a week.
Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week ,Part time agents work 20 hours a week but are only on calls 17 hours per week .
⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940
⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940
Option A
⇒35×15×7+17×7×15
= 3675+1785
= 5460
Option B
⇒35 ×7×20+17×7×7
=4900 +833
= 5733
Option C
⇒35×20×7 +17×20×7
=4900+2380
=7280
Option D
⇒25 × 35×7+17×7×5
=6125 +595
=6720
Option E
⇒28×35×7+17×7×10
=6860+1190
=8050
Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.
I’m not sure if it’s add or multiple the sides of each I don’t know if this even helped lol
Answer:
20 Outcomes.
Step-by-step explanation:
A-1 A-2 A-3 A-4
B-1 B-2 B-3 B-4
C-1 C-2 C-3 C-4
D-1 D-2 D-3 D-4
E-1 E-2 E-3 E-4
Hope this helps!
Be more specific on the first one
Answer:;4.4
Step-by-step explanation: Since it varies inversely we know G times H squared is equal to some constant, k. So we have G*H*H=k. We are told that when H=4, G=.25. Plugging this in, we have .25*4*4=k. This simplifies to 4=k. Our new equation is G*H*H=4. Now, we want to solve for G when H=.3. We plug it in. G*.3*.3=4 => G*.09=4. G=4/.09. This means G is approximately 44.4.
