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Genrish500 [490]
3 years ago
11

One number is 20 times another number. The product of the two numbers is 180. Write an equation and use it to find all pairs of

numbers that satisfy the
Mathematics
2 answers:
nadezda [96]3 years ago
8 0
Y = 20x

y • x = 180

180/x = y

180/x = 20x

180 = 20x^2

x^2 = 6

x = + or - 3

Therefore y must equal + or - 60.
timama [110]3 years ago
5 0

Answer: the Smaller number is 3

The larger number is 60

Step-by-step explanation:

Let x represent the smaller of the numbers.

Let y represent the larger number.

One number is 20 times another number. This means that

y = 20x

The product of the two numbers is 180. This means that

xy = 180- - - - - - - - - -1

Substituting y = 2x into equation 1, it becomes.

x × 20x = 180

20x² = 180

x² = 180/20 = 9

x = √9

x = 3

y = 20x = 20 × 3

y = 60

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Oksanka [162]

Answer:

3 bulbs should be flawed

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2+ 18 = 20

20 bulbs were examined

2/20  = 1/10 were flawed

looking at the next 30 bulbs

30 * 1/10 = 3

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5 0
3 years ago
A rectangle has a height of a² + 3 and a width of a² + 2a + 5.
valentina_108 [34]

Answer:

Area =  a^4+2a^3+8a^2+6a+15

Step-by-step explanation:

The area of a rectangle is given by:

Area = Height * Width

The expressions for height and width are given. We just need to multiply and add like terms (if applicable) to find the expression for the area of the rectangle.

Remember to use distributive property:

(a+b)(x+y) = ax + ay + bx + by

Thus, we have:

(a^2+3)(a^2+2a+5)\\=(a^2)(a^2)+(a^2)(2a)+(a^2)(5)+3a^2+6a+15\\=a^4+2a^3+5a^2+3a^2+6a+15\\=a^4+2a^3+8a^2+6a+15

THis is the expression for area.

5 0
3 years ago
Can someone give me some tips of how to study. I have already tried writing everything in my lesson but it doesn't seem to work
Ainat [17]
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8 0
3 years ago
Can you please show working out for $4,000 at 3% for 4 years
dedylja [7]
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3 years ago
Let an integer be chosen at random from the integers 1 to 30 inclusive. Find the probability that the integer chosen is not even
mylen [45]
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Thank you for letting me answer your question here on brainly. I like to help people as much as I can, so please let me now if my answers provide any help to you. It means a lot to me to know that my questions help provide support to people in the community to need help. If you want extra help, you can PM me! I get lot of PMs tough, so it might take a while to respond, my apologies. Thanks for reading this, and have a great day! ~ brainily user, Lillyxrose
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3 years ago
Read 2 more answers
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