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Nezavi [6.7K]
3 years ago
10

Write an equation that expresses the following relationship. d varies directly with the cube of w and inversely with p. In your

equation, use k as the constant of proportionality.

Mathematics
2 answers:
Delvig [45]3 years ago
8 0

The formula for the indicated variable is d = k w³ / p

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed {m = \frac{y_2 - y_1}{x_2 - x_1} } }

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large { \boxed {y - y_1 = m ( x - x_1 ) } }

Let us tackle the problem.

This problem is about directly and inversely proportional.

<u>Given</u> :

d varies directly with the cube of w → \boxed {d \propto w^3}

d varies inversely with p → \boxed {d \propto p^{-1} }

∴ \large {\boxed {d \propto ( w^3 \times p^{-1} )} }

From the above relationship, we can write the equation for the variable d i.e:

\large { \boxed {d = k \frac{w^3}{p} } }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

pantera1 [17]3 years ago
5 0

Here d varies directly with cube of w, and inversely with p. So w cube have to be in the numerator and p have to be in the denominator. And we need to use k for constant of proportionality. Therefore the required equation is

d=\frac{kw^3}{p}

In direct proportionality, the relatioship is linear that is as w increases, d increases and as w decreases d decreases and for inverse, it is opposite .

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