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3 years ago

20(5b+14) and it says to multiply

Mathematics

2 answers:

SIZIF [17.4K]3 years ago

6 0

The answer is 100b+280

nata0808 [166]3 years ago

5 0

100b+280
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I need help on this asap

guapka [62]

Answer:

the answer to this is

$315

3 0

1 year ago

Read 2 more answers

-3(6-4x)-5(-x+8)= 4(2-5x )

loris [4]

You may express it as :

-18+24x+5x-40=8-20x
49x=56
x=56/49

5 0

3 years ago

If 10% of men are bald, what is the probability that fewer than 100 in a random sample of 818 men are bald? (Answers must be in

Greeley [361]

Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

Step-by-step explanation:

Given that;

p = 10% = 0.1

so let q = 1 - p = 1 - 0.1 = 0.9

n = 818

μ = np = 818 × 0.1 = 81.8

α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58

Now to find P( x < 100)

we say;

Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12

P(x<100) = P(z < 2.12)

from z-score table

P(z < 2.12) = 0.9830

Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

4 0

3 years ago

Maria earns $80 per day working at a gas station. Write an algebraic expression to represent the amount of money she will earn i

Simora [160]

Answer:

The algebraic expression is 80d

Step-by-step explanation:

Maria's earnings per day = $80

Number of days= d

Total earnings for d days:

80d

Where,

80 is earnings per day

d is number of days

The algebraic expression is 80d

Algebraic equation is

y= 80d

Where

y= total income earned in d days

The expression is different from am equation because of the equal to sign(=)

3 0

3 years ago

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below

5 0

2 years ago