the assumption being that the endpoints are two continuous points in the pentagon, Check picture below.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[2-(-1)]^2+[3-4]^2}\implies d=\sqrt{(2+1)^2+(3-4)^2} \\\\\\ d=\sqrt{9+1}\implies d=\sqrt{10}~\hfill \stackrel{\stackrel{~\hfill \stackrel{\textit{5 sides}}{}}{\textit{perimeter of the pentagon}}}{5\sqrt{10}}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B2%7D~%2C~%5Cstackrel%7By_2%7D%7B3%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B%5B2-%28-1%29%5D%5E2%2B%5B3-4%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%282%2B1%29%5E2%2B%283-4%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B9%2B1%7D%5Cimplies%20d%3D%5Csqrt%7B10%7D~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7B~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B5%20sides%7D%7D%7B%7D%7D%7B%5Ctextit%7Bperimeter%20of%20the%20pentagon%7D%7D%7D%7B5%5Csqrt%7B10%7D%7D)
We use the ratio x:360 to find portions of the circle (again, through the ratio)
so we use 60/360 = x/30 in^2
1/6 = x/ 30
x = 5.
The answer is 5 in^2
Answer: 25/676
Step-by-step explanation:
Number of possible outcomes = 26
In other to win, one must draw must be either (A, E, I, O or U)
Therefore required drws to win = 5
First draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Second draw:
P(win) = Total required outcome / Total possible outcome
P(win) = 5/26
Therefore,
P(winning twice) = (5/26) × (5/26) = 25/676
Determine<span> whether a triangle with the given </span>lengths<span> is a </span>right triangle<span> or not. </span>Find<span> the </span>missing side<span> in each of the following </span>right triangles<span>. 2.</span>8 cm<span>, ') = 7 </span>cm<span> (</span><span>b) $% = 6 </span>cm<span>, %& = </span>8 cm<span>, $& = 10 </span>cm<span> (c) 34 = 17 </span>cm<span>, 45 = </span>8 cm<span>, 35 = </span>15 cm<span> 3.
</span>Use the Pythagorean Theorem to find<span> each </span>missing<span> measure. 1. 2. Example 1A</span>: Calculating theLength<span> of a </span>Side<span> of a </span>Right Triangle<span>. 12 </span>cm<span> , </span>82<span> + </span>152<span> = 17</span>2<span>.
</span>8.6.7, 8<span>.EE.2. When viewed from the </span>side<span>, the shape of some wooden waterskiing ramps is a, So, the hypotenuse is </span>15<span> inches long. Check: 02 + Write an equation you could use to </span>find<span> the length of the </span>missing side<span> of 20 </span>cm<span>. 18 yd lf the </span>sides<span> of a </span>triangle<span> have </span>lengths<span> 0,13, and c units such that 02 + is)2 = C 2</span>
