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Sonbull [250]
3 years ago
11

What is a flat irreguraly shaped cell that make up the top and, bottom layers of leaves

Biology
1 answer:
prisoha [69]3 years ago
5 0

Answer:

Epidermal

Explanation:

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Briefly describe the process you can use if you cannot find an ebp that matches your students and your resources.
luda_lava [24]
;ld;ldf d;lj lkdsjf lkds fj a;lkdjf lkdj fklsd jldsf jlkd fa;ls d fjkl;d f;aslf jlkds  f;lkf jewiory kjdfj kldfj dkfldk f;lkdafj;ldkf hahahahahahaha get trolled

8 0
3 years ago
2. Dominant trait: cleft chin (C) Mother’s gametes: Cc
andre [41]

.2. Offspring Genotypes will be Cc or cc.

     Offspring phenotypes : Cleft chin or no cleft chin.

    % chance child will have cleft chin: 50%

3.  % chance child will have arched feet: 25%

4.  % chance child will have blonde hair:  50%

5.  % chance child will have normal vision: 25%

 

Explanation:

CASE 1 :

 Dominant trait: cleft chin (C)

    Recessive trait: lacks cleft chin (c)

    Father’s gametes: cc

    Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and  c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents=  \frac{1}{2}C + \frac{1}{2} c........(i)

Gametes of cc parents =<u> </u>\frac{1}{2}c + \frac{1}{2}c .........(ii)

Combining (i) and (ii) we get,

\frac{1}{2}  Cc + \frac{1}{2} cc                              

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin  =\frac{0.5}{1} ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous   (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

     A from mother, a from father =Aa

     a from mother, A from Father = Aa

     a from mother, a from father = aa

Gametes of Aa parent =\frac{1}{2} A + \frac{1}{2} a

Gametes of other Aa parent = \frac{1}{2} A + \frac{1}{2} a

                                       <u>..................................................................................</u>

                                              \frac{1}{4} AA + \frac{1}{4} Aa

                                                                           +  \frac{1}{4} Aa +\frac{1}{4} aa

                                   <u>..........................................................................................</u>

                                <u>\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa</u>

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = \frac{0.25}{1} × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive  (bb)

Father’s gametes: Heterozygous  (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in  half  Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous  (Ff)

Father’s gametes: Heterozygous  (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF  then phenotype farsightedness

Genotype Ff then phenotype  farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

 

3 0
3 years ago
A patient was admitted to the hospital medical floor with a diagnosis of chronic bronchitis, which is an inflammation of the air
mote1985 [20]
In the case of chronic bronchitis or chronic inflammation of the airways, cyanosis or the bluish discoloration of the skin results from the reduced levels of oxygen in the blood. With reduced oxygen levels, the blood in the arteries will not be bright red in color but rather be brownish just like venous blood and this reflects in the skin as bluish in color. 
7 0
2 years ago
Evolution occurs in response to a change in the environment. Environmental change often involves other species of organisms. Whi
Serjik [45]

Answer:

c is the answer

hope it helps you

3 0
2 years ago
With the following crosses of pea plants, give the flower color of offspring and the ratio expected (red is dominant).
Ray Of Light [21]
So, both pea plants being crossed are homozygous reds, which means that their alleles look like: RR. This means that there are only R alleles present, so you can't have any other kind of flower without a genetic mutuation.
This means that the offspring must have a red flower, which would occur 100% of the time.
5 0
3 years ago
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