Answer:
H-4
Step-by-step explanation:
Let's simplify step-by-step.
8+H−12
=8+H+−12
Combine Like Terms:
=8+H+−12
=(H)+(8+−12)
=H+−4
Answer: 
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10
9c + 4 = 49
The numbers by themselves represent the amount of dollars spent (4 and 49), but since you don’t know the amount of money each candy bar cost, you would put the amount of candy bars and a variable next to it to then solve ($5 per bar)
1. The values of p and q are: p=31 and q= 4
2. B(11, 29/5)
Further explanation:
<u>1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.</u>
Given:
M = (15. 1)
(x1, y1) = (p, -2)
(x2, y2) = (-1, q)
The formula for mid-point is:

Hence,
p=31
q=4
<u>2. M is the midpoint of the straight line joining point A (3. 1/5) to point B.If m has coordinates (7. 3), find the coordinates of B.</u>
Here,
(x1,y1) = (3, 1/5)
(x2, y2) = ?
M(x,y) = (7,3)
Putting values in the formula of mid-point

So, the coordinates of point B are (11, 29/5) .
Keywords: Finding mid-point, Finding coordinates through mid-point
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