Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. 2x+y+
z=-3 3x-5y+3z=-4 5x-y+2z=-2
1 answer:
Answer:
(x, y, z) = (1, -1, -4)
Step-by-step explanation:
A suitable graphing or scientific calculator can find the reduced row-echelon form for you. There are on-line calculators that will do that, too.
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In general, if you want to do this by hand, you want to use row operations on the augmented matrix to make the diagonal elements 1 and the off-diagonal elements 0 as shown in the attached result.
If a[i,j] represents the element at row i, column j, you do that by dividing row i by a[i, i] (to make a[i, i] = 1), then subtracting the product of row i and a[k,i] from row k. (for all rows k ≠ i) For this 3-row matrix, repeat these steps for i = 1 to 3.
In the general case of an n by n+1 augmented matrix, you will be doing n^2 row operations, each one involving evaluation of n+1 expressions. The work rapidly grows with matrix size, so readily justifies use of a calculator.
As with many "elimination" problems, appropriate choice of sequence can reduce the work. The above algorithm always produces the reduced row-echelon form, but may result in messy arithmetic along the way.
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Answer:
The first option is the correct one, the area of the shaded portion of the circle is
[/tex](5 \pi -11.6)ft^2[/tex]
Step-by-step explanation:
Let us first consider the triangle + the shadow.
The full area of the circle is the radius squared times pi, so
A=
Since , the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus
If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from .
The area of the triangle is given by
Thus the area of the shaded portion of the circle is