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timofeeve [1]
2 years ago
12

Please need help asap ❤️You have placed your money in a bank account with an interest rate of 5.8% compounding annually. After 5

years you have $9090 how much did you put in the bank originally? Plzzzz ASAP plzzzzzz
Mathematics
1 answer:
xenn [34]2 years ago
5 0
$6857 was originally kept
Hope it helps
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Steve has 2 cups of flour. One of his recipes requires cup of flour. What is the
Dennis_Churaev [7]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Which expression represents the volume of the rectangular prism shown? A) 3x + 8 B) x2 + 3x C) x3 + 23x2 D) x3 + 8x2 + 15x
lianna [129]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
What is 33/7 divided by 1 13/14
MA_775_DIABLO [31]
(33/7) / (1 13/14)
= (33/7)/ (27/14)
= (33/7)* (14/27)
= 22/9
= 2 4/9

The final answer is 2 4/9~

3 0
3 years ago
Stress at work: In a poll conducted by the General Social Survey, 81% of respondents said that their jobs were sometimes or alwa
andrew-mc [135]

Answer:

We are given that  81% of respondents said that their jobs were sometimes or always stressful.

So, p = 0.81

(a) Approximate the probability that 150 or fewer workers find their jobs stressful.

x = 150

p = 0.81

n = 175

So, \frac{x}{n} =\widehat{p}

\frac{150}{175} =\widehat{p}

0.8571=\widehat{p}

Formula : z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

z=\frac{0.8571-0.81}{\sqrt{\frac{0.81(1-0.81)}{175}}}

z=1.5882

Refer the z table

So, P(z<150)=0.9429

So, the probability that 150 or fewer workers find their jobs stressful is 0.9429

b) Approximate the probability that more than 140 workers find their jobs stressful.

x = 140

p = 0.81

n = 175

So, \frac{x}{n} =\widehat{p}

\frac{140}{175} =\widehat{p}

0.8=\widehat{p}

Formula : z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

z=\frac{0.8-0.81}{\sqrt{\frac{0.81(1-0.81)}{175}}}

z=-0.3372

P(z<140) = 0.3707

P(z>140)=1-P(z<140)=1-0.3707=0.6293

So, the probability that more than 140 workers find their jobs stressful is 0.6293

c) Approximate the probability that the number of workers who find their jobs stressful is between 146 and 150 inclusive.

x = 146

p = 0.81

n = 175

So, \frac{x}{n} =\widehat{p}

\frac{146}{175} =\widehat{p}

0.8342=\widehat{p}

Formula : z=\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

z=\frac{0.8342-0.81}{\sqrt{\frac{0.81(1-0.81)}{175}}}

z=0.816

From part a) P(z<150)=0.9429

So,P(z<150)-P(z<146)=0.9429 - 0.8342=0.1087

Hence the probability that the number of workers who find their jobs stressful is between 146 and 150 inclusive is 0.1087

7 0
2 years ago
IM GIVING 20 POINTS
Alla [95]

Answer:

you get 9/25

Step-by-step explanation:

formula for area of square

=s^2

plug in

3/5^2

calculate

you get 9/25

8 0
2 years ago
Read 2 more answers
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