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2 years ago

Help me to find AC please

Mathematics

1 answer:

spin [16.1K]2 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

Since the triangle is right use cosine or sine to solve for AC

note cos30° = $\frac{\sqrt{3} }{2}$ , thus

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{AC}{BC}$ = $\frac{AC}{\frac{10}{3} }$ and

$\frac{AC}{\frac{10}{3} }$ = $\frac{\sqrt{3} }{2}$ , that is

$\frac{3x}{10}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

6x = 10 $\sqrt{3}$ ( divide both sides by 6 )

x = AC = $\frac{10}{6}$ $\sqrt{3}$ = $\frac{5}{3}$ $\sqrt{3}$

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