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2 years ago

Help me to find AC please

Mathematics

1 answer:

spin [16.1K]2 years ago

4 0

Answer:

see explanation

Step-by-step explanation:

Since the triangle is right use cosine or sine to solve for AC

note cos30° = $\frac{\sqrt{3} }{2}$ , thus

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{AC}{BC}$ = $\frac{AC}{\frac{10}{3} }$ and

$\frac{AC}{\frac{10}{3} }$ = $\frac{\sqrt{3} }{2}$ , that is

$\frac{3x}{10}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

6x = 10 $\sqrt{3}$ ( divide both sides by 6 )

x = AC = $\frac{10}{6}$ $\sqrt{3}$ = $\frac{5}{3}$ $\sqrt{3}$

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Step-by-step explanation:

If it is 5 + 2/3

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Step (1)

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Answer:

a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

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Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

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$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

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Part c

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Part d

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Part e

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