AB = √(5-0)^2 + (4-0)^2 = √25+16 = √41
BC = √(0-5)^2 + (8-4)^2 = √25+16 = √41
CD = √(-5 - 0)^2 + (4-8)^2 = √25+16 = √41
AD = √(-5-0)^2 + (4-0)^2 = √25+16 = √41
All the sides are equal so it is either a square or a rhombus.
The distance from A to C on the x axis is: 8-0 = 8 units.
The distance from B to D on the Y axis is: 5 - - 5 = 10 units.
Because the two distances are not the same, it is not a square.
The answer is 4. AB=BC ; therefore, ABCD is a rhombus.
First I find the individual widget weight
81 - 73 = 2x
8 = 2x
x = 4
Then I find how many widgets were left
73 - 1 = 4y
72 = 4y
18 = y
Y is the amount of widgets left, therefore the amount left is 18
6,000,000 + 7,000+ 200 is your expanded form
hope this helps
<span>the line over the 28 means the 28 repeats forever.
1.282828.... and so on
let x be the rational number 1.28...
we can use this trick:
100*1.282828....= 128.282828...
(the decimal 28 part repeats)
100x = 128.28...
next:
100x - x = 128.282828... - 1.282828...
the .282828... part will be subtracted away
99x = 127
divide both sides by 99 to get
x= 127/99</span>
If i'm not wrong,i think the answer is:
30％=0.3
X=0.3+12=12.3
