Answer:
8.0 seconds to the nearest tenth,
Step-by-step explanation:
h=-16t^2 +vt + c.
-16t^2 + 116t + 101 = 0
t = [ -116 + /- √(116^2 - 4*-16*101) ] / (-32)
t = (-116 +/- √19920) / (-32)
t = -0.79, 8.036 (we ignore the negative root)
The time in flight = 8.036 seconds.
Answer:
6 samples
Step-by-step explanation:
Given :
Sample size, = n
Standard deviation, = 6000
Margin of Error = 2000
Confidence interval, α = 95%
Zcritical at 95% = 1.96
n = (Zcritical * σ) / margin of error
n = (1.96 * 6000) /2000
n = 11760 / 2000
n = 5.88
n = 6 samples
Equilateral triangle have the same side lengths. Perimeter = sum of all sides
(4x - 3) + (4x - 3) + (4x - 3) = 63
Remove parentheses
4x - 3 + 4x - 3 + 4x - 3 = 63
Combine like terms
12x - 9 = 63
12x = 72, x = 6
Solution: x = 6
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1,
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
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