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avanturin [10]
2 years ago
13

Does anyone know how to solve this The answer is B but can anyone explain why

Mathematics
1 answer:
Lana71 [14]2 years ago
6 0

Answer:

B. (0,-1)

Step-by-step explanation:

see.. i'm not rude.... :/

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Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector \vec{v} in some vector space \mathbb R^n we have

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This is the component form. I don't like that way. It is probably used in high school, but

\vec{v} =  \begin{pmatrix} a\\ b\\ \end{pmatrix}

is preferable because the inner product on \mathbb R^n is defined to be

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4.

For this question, I think you meant

vectors

\vec{u_1} = (-8, 12)

\vec{u_2}  = (13, 15)

Once

\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}

Considering that the dot product is

\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76

and the norm of \vec{u_1} is ||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}

and the norm of \vec{u_2} is ||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}

Thus,

\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}

\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:because

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