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avanturin [10]
2 years ago
13

Does anyone know how to solve this The answer is B but can anyone explain why

Mathematics
1 answer:
Lana71 [14]2 years ago
6 0

Answer:

B. (0,-1)

Step-by-step explanation:

see.. i'm not rude.... :/

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A fair tossed 10 times . Find the probability of obtaining (i) exactly four heads (ii) 3 heads and 7 tails (iii) at least one he
vodka [1.7K]

Answer:

0.205 ; 0.117 ; 0.999

Step-by-step explanation:

Using binomial probability distribution :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

Probability of success, p = 0.5

P(x = 4) = 10C4 * 0.5^4 * 0.5^6

P(X = 4) = 0.205078125

B.) 3 heads and 7 tails

P(X = 7) = 10C7 * 0.5^7 * 0.5^3

P(X = 7) = 120 * 0.0009765625

P(X = 7) = 0.117

P(atleast one head)

P(x greater than equal to 1) = p(x =1) +... P(x = 10)

Using a binomial probability calculator :

P(x greater than equal to 1) = 0.999

3 0
2 years ago
Yadier killed 3 4/5 miles from the Nature Center to the waterfall. Then he hiked another 2 2/3 miles to Overlook Point. How far
EastWind [94]

Answer: estimate 7

exact: 6 7/15

Step-by-step explanation: for the estimate round 3 4/5 to 4 and 2 2/3 to 3 and 4 + 3 = 7

for the exact number convert 3 4/5 to 3 12/15

and convert 2 2/3 to 2 10 /15

then add 3 + 2 = 5

and 12/15 + 10/15 = 22/15

convert 22/15 to a mixed number which is 1 7/15

then 5 + 1 7/15

answer 6 7/15

hope this helps mark me brainliest if it helped

7 0
3 years ago
Mr.Ward runs a lot. He ran 45 minutes each day, 5 days each week , for 16 weeks . In that time, he ran 450 miles. What was his a
Savatey [412]

Answer:

7.5 miles per hour.

Step-by-step explanation:

We have been given that Mr. Ward runs a lot. He ran 45 minutes each day, 5 days each week, for 16 weeks.

First of all, we will find time for that Mr. Ward ran in 16 weeks.

We will multiply 5 by 16 to find number of days for that Mr. Ward ran and then we will multiply the result by 45 minutes to find the time.

\text{Time for that Mr. Ward ran in 16 weeks}=16\times 5\times 45\text{ minutes}

\text{Time for that Mr. Ward ran in 16 weeks}=3600\text{ minutes}

Now, we will divide 3600 minutes by 60 minutes to convert time into hours as:

\text{Hours}=\frac{3600}{60}=60

Now, we will divide 450 miles by 60 hours to find Mr. Ward's average speed as:

\text{Mr. Ward's average speed}=\frac{450\text{ miles}}{\text{60 hours}}

\text{Mr. Ward's average speed}=\frac{7.5\text{ miles}}{\text{ Hour}}

Therefore, Mr. Ward's average speed in 7.5 miles per hour.

7 0
3 years ago
The intercepts of the circle (x-1)^2 + (y-2)^2 = 10 are ?
IRISSAK [1]

y-intercept:  Let x = 0 and solve for y:

(x-1)^2 + (y-2)^2 = 10 => (-1)^2 + y^2 - 4y + 4) = 10

                                =>  1 + y^2 - 4y + 4 = 10, or   y^2 - 4y  -5 = 0

                                The solutions of this quadratic are y = 5 and y = -1.

                                Thus, the y-intercepts are (0, 5) and (0, -1).

Now find the x-intercepts:  Let y = 0 and solve the resulting equation for x:

(x-1)^2 = 10 - (-2)^2, or (x-1)^2 = 10 - 4 = 6.

Taking the sqrt of both sides, x - 1 = plus or minus sqrt(6), or:

                                                  x = 1 +√6 and x = 1 - √6, so that the x-intercepts

                                                  are (1+√6, 0) and (1-√6, 0).

8 0
3 years ago
PLEASEEE I DONT KNOW HOW TO DO ITTTT. THE 35.8 IS RIGHT BUT I CANT GET MEASURE OF ANGLE C AND A I GOT 46.2 for A AND 70.8 for C
Rashid [163]

Answer:

Hope it helps....!!!!!

Step-by-step explanation:

AB = c = 38

BC = a = 29

AC = b

Angle ABC = 63 degrees

Solving for AC   "b":

Cosine rule: c^2 = a^2 * b^2 -2ab * cos C

38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)

1444 = 841 * b^2 - 58 * b * 0.955

(1444 + 58)/0.955 = b^2 * b

1572.77486911 = b^3

11.62935 = b

11.63 = b (rounded to two decimal places)

Now solving for angle A:

Sine rule: a/sinA = b/sinB

29/sinA = 11.63/sin(63)

sinA/29 = sin(63)/11.63

sin A = (sin(63)/11.63) * 29

sin A = 0.41731

A = sin^-1 (0.41731)

A = 24 degrees 39 minutes 53 seconds

Now solving for angle C:

Sine rule: c/sinC = b/sinB

38/sinC = 11.63/sin(63)

sinC/38 = sin(63)/11.63

sin C = (sin(63)/11.63) * 38

sin C = 0.54682

C = sin^-1 (0.54682)

C = 33 degrees 8 minutes 56 seconds

3 0
3 years ago
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