We need more information to answer.
When x = 0, the value of f(x) is 2. You can see why below
f(x) = (2^x) + 1
f(0) = (2^0) + 1
f(0) = 1+1
f(0) = 2
So the point (0,2) is on the curve. This is visually shown as the y intercept (the location where the curve crosses the y axis)
When x = 2, the value of f(x) is 5
f(x) = (2^x) + 1
f(2) = (2^2) + 1
f(2) = (4) + 1
f(2) = 5
So (2,5) is another point on this curve
Find the slope of the line through these two points
m = (y2 - y1)/(x2 - x1)
m = (f(2) - f(0))/(2 - 0)
m = (5 - 2)/(2 - 0)
m = 3/2
m = 1.5
The slope as a fraction is 3/2
The slope as a decimal is 1.5
So the rate of change is 1.5
Answer:
Second graph only.
Step-by-step explanation:
The standard equation of a parabola is ax^2+bx+c where a,b and c are coefficients.
If the coefficient of (a) is positive then the parabola is concave upwards (as in picture 1)
If the coefficient of (a) is negative then the parabola is concave downwards as in picture 2.
I think its either 9 or 10
