What is the product of (2x+3) and (4x^2-6x+9)?

Mathematics

1 answer:

gogolik [260]3 years ago

4 0

Answer:

=8x^3+27

Step-by-step explanation:

First you are going to multply 2x by all of the other numbers in the 2nd parentheses, then do the same with 3. By doing this you should get and answer then combine like terms.

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Solve each system by elimination by multiplying both equations. eliminate y first. show all work.

Alex17521 [72]

First $\mathrm{Multiply\:}10x-3y=18\mathrm{\:by\:}3:\quad 30x-9y=54$
Then $\mathrm{Multiply\:}6x-10y=-22\mathrm{\:by\:}5:\quad 30x-50y=-110$
To get $\begin{bmatrix}30x-9y=54\\ 30x-50y=-110\end{bmatrix}$
So...
$30x-50y=-110 \ \textgreater \ \begin{bmatrix}30x-9y=54\\ -41y=-164\end{bmatrix}$
$-41y=-164 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}-41 \ \textgreater \ \frac{-41y}{-41}=\frac{-164}{-41}$
To get y = 4.
$\mathrm{For\:}30x-9y=54\mathrm{\:plug\:in\:} \:y=4 \ \textgreater \ 30x-9\cdot \:4=54$
$\mathrm{Multiply\:the\:numbers:}\:9\cdot \:4=36 \ \textgreater \ 30x-36=54 \ \textgreater \$
Next $\mathrm{Add\:}36\mathrm{\:to\:both\:sides} \ \textgreater \ 30x-36+36=54+36 \ \textgreater \ \mathrm{Simplify} \ \textgreater \ 30x=90$
Finally $\mathrm{Divide\:both\:sides\:by\:}30 \ \textgreater \ \frac{30x}{30}=\frac{90}{30} \ \textgreater \ x = 3$
Therefore our solutions are y = 4, x = 3

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Without multiplying circle whether each product is greater than, less than, Equal to the whole number

mafiozo [28]

Step-by-step explanation:

4 × (1/7) Less Than
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