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stich3 [128]
3 years ago
13

What is the product of (2x+3) and (4x^2-6x+9)?​

Mathematics
1 answer:
gogolik [260]3 years ago
4 0

Answer:

=8x^3+27

Step-by-step explanation:

First you are going to multply 2x by all of the other numbers in the 2nd parentheses, then do the same with 3. By doing this you should get and answer then combine like terms.

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Write 54 + 63 as the product of the<br> GCF of 54 and 63 and another sum.
photoshop1234 [79]

Answer:

9(6+7)

Step-by-step explanation:

5 0
3 years ago
it was recently estimated that domestic vehicles out numberforegin vehicles by about six to five. if there are 2673 vehicles in
klio [65]

The question is an example of a ratio problem. This implies that

\begin{gathered} \text{Domestic vehicles ratio=6} \\ \text{Foreign vehicles ratio=5} \\ Sum\text{ of vehicles ratio =5+6=11} \end{gathered}

Therefore, le the number of domestic vehicles be x. We can say that;

\begin{gathered} \frac{6}{11}=\frac{x}{2673} \\ 11x=16038 \\ x=\frac{16038}{11} \\ x=1458 \end{gathered}

Answer: 1458

7 0
1 year ago
F(x) = x + 2 g(x) = x – 4
wariber [46]

Answer:

G= -2/x, x \neq 0

X= -2/g, g \neq 0

Step-by-step explanation:

5 0
2 years ago
A certain car rental location charges a daily fee as well as a mileage charge. On one trip a businessman rented a car for the da
nikklg [1K]

Answer:

x\approx 267\ miles

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

f(x)=mx+b

For the problem at hand, we must pick the adequate variables according to the data provided.

The question states the charge for renting a car is a function of the mileage. It also provides two points from which we can build our model. Let's set the following variables:

c = the charge for renting a car in dollars

x = the distance driven by the businessman in miles

Representing the ordered pair as (x,c), we have the points: (150,79) and (65,63.70). Our model will be expressed as:

c = mx+b

We must find the values of m and b with the data provided. Substituting the first point:

79 = 150m+b

Substituting the second point:

63.70 = 65m+b

Both equations form the following system:

\left\{\begin{matrix}150m+b=79\\ 65m+b=63.70 \end{matrix}\right.

Subtracting both equations:

150m-65m=79-63.70

Note the variable b was canceled out in the operation, leaving only the variable m to solve. Joining like terms:

85m=15.3

Solving:

m=15.3/85=0.18

From the first equation

79 = 150m+b

Solving for b:

b=79-150m=79-150(0.18) = 52.

The model for the problem is:

c=0.18x+52

Now we need to calculate how many miles (x) could be driven for c=$100. From the equation above, substitute c=100

100=0.18x+52

Solve for x:

0.18x+52=100

0.18x=100-52=48

x=48/0.18=266.67

Rounding to the closest integer:

\boxed{x\approx 267\ miles}

7 0
3 years ago
Solve 7p - 4 + 12p = -3 (5 + p) Can you show the work please?
prisoha [69]
7p - 4 + 12p = -3(5 + p)
7p - 4 + 12p = -15 - 3p
        + 4              + 4
7p + 12p    = -11 - 3p
        + 3p                + 3p
22p             = -11

p = -1/2  Answer
7 0
3 years ago
Read 2 more answers
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