Answer:
The answer is (-5,2)
Step-by-step explanation:
So we have 2 equations and we need to solve them by substitution.
1) y = 4x + 22
2) 4x – 6y = –32
Since we already have y isolated in equation #1, we'll use that value in equation #2:
4x - 6(4x + 22) = -32
4x - 24x - 132 = -32
-20x = 100
x = -5
Then we put that value of x in the first equation:
y = 4 (-5) + 22 = -20 + 22 = 2
The answer is then (-5,2)
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Solve for x:
3(x - 5) = 6
Distribute the 3 to the variables inside the parenthesis
3x - 15 = 6
Add 15 to both sides to cancel out the "-15"
3x = 21
Divide both sides by 3
x = 7
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Answer:
~ 2y-1
Explanation:
~ There’s no like terms for us to collect
~ So we just leave it as it is, we only have to get rid of the bracket and that’s the answer
Answer:
Step-by-step explanation:
It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get
Now, From ΔABC and ΔHBC, we have
∠ABC=∠BHC(each90)
∠ACB=∠HCB (Common)
By AA similarity, ΔABC is similar to ΔHBC.
Thus, using the similarity condition, we get
<span>-3|15 - s| + 2s^3
=</span><span>-3|15 - (-3)| + 2(-3)^3
= </span><span>-3|18| -54
= -54 - 54
= -108</span>
