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2 years ago

A circle has a 10 centimeter radius. Find the area of the circle to the nearest tenth. (Use 3.14 for ?)

Mathematics

1 answer:

pickupchik [31]2 years ago

3 0

Answer:

314.2 cm^2

Step-by-step explanation:

The formula for the area of a circle of radius r is A = 3.14r^2.

With r = 10 cm, r^2 = 100 cm^2, and so the area of this circle is 314.2 cm^2, to the nearest tenth.

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A taxi service charges a flat rate for the first

Kazeer [188]

Answer:

The taxi charges $10 as the flat rate for the first 3 miles and $2.50 for each additional mile.

Step-by-step explanation:

3 0

3 years ago

Need some help please <br> Thank you

Reil [10]

Answer: Ratio of black horses to all horses = 59/62

Step-by-step explanation:

Total number of horses = 62

Total number of white horses = 3

Assuming that the rest horses are black. That means the total number of black horses would be 62-3 =59. So there are 59 black horses and there are 3 white horses.

Ratio of black horses to all horses will be the total number of black horses / the total number of horses.

Ratio of black horses to all horses

= 59/62 or 59:62

It can also be expressed in decimals which will become

0.952

5 0

3 years ago

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

3 years ago

Can someone help me learn to solve this?

kondaur [170]

Answer:

x = 110°

Step-by-step explanation:

Given that AB = AD then Δ ABD is isosceles and the base angles are congruent, that is

∠ ABD = ∠ ADB = 35°

The sum of the 3 angles in the triangle = 180°, that is

x + 35° + 35° = 180°

x + 70° = 180° ( subtract 70° from both sides )

x = 110°

5 0

3 years ago

How many solutions does the system of linear equations 6a + 3b = 12 and<br> 6a - 3b = 12 have?

Olin [163]

Answer:

One solution

Step-by-step explanation:

Lets solve it for b

3b= -6a+12

3b= 6a-12

Simplifying

b= -2a+4

b= 2a+4

Both have same slope and intercept hence both lines are going to intersect at one point. So the equations are having one solution.

3 0

3 years ago