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Snezhnost [94]
3 years ago
15

If you are good at 9th grade math tell me and send me your number so we can text I really need a tutor or just help please

Mathematics
2 answers:
horrorfan [7]3 years ago
6 0

Answer:

I'm super sorry that i can't help but if i could get you to my brother and ask him for his number i bet he'll be able to help. ;) and if u r a girl he's pretty desperate for a girlfriend so ..... yeah

Step-by-step explanation:

hope this helps and also hope my brother can help byyyyyeeeee

spin [16.1K]3 years ago
4 0
I’m also in 9th grade and need help
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Nate weighs 6 pounds more than William. William weighs 3 pounds more than Todd.
djyliett [7]

Answer:

William weighs 111 pounds.

Step-by-step explanation:

N = x+6

W = x

T = x-3

x+6+x+x-3=336

3x + 3 = 336

3x = 336 - 3

x = 333/3

x = 111

4 0
2 years ago
My grade is a 77%, if i get a 0% on a paper worth 30% of my grade, what will my grade be now??
blsea [12.9K]
Grade=Paper+Other
Grade=(Grade_{paper}\times Value_{paper})+(Grade_{other}\times Value_{other})
Grade=(0 \times 30\%)+(77\% \times (1-30\%))
Grade=(0 \times 30\%)+(77\% \times 70\%)
Grade=0+53.9\%
Grade=53.9\%
6 0
3 years ago
A greater number than -8​
sertanlavr [38]
Practically anything above -8
Such as -7, 2, 15600, anything not under -7.9
6 0
3 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
Find the distance between points P(5, 1) and Q(1, 3) to the nearest tenth.
bonufazy [111]

Answer:

Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq

=√4+9

=√13 <--

or

3.6 units

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is: 3.6

Thus, the distance between the given two points is 3.6 units.

So you choose 13 or 3.6 Hope this helps :)

3 0
3 years ago
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