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ratelena [41]
3 years ago
7

If (angle)1 = 7x and (angle)4 = 3x + 20, what is the value of x?

Mathematics
2 answers:
Semenov [28]3 years ago
7 0
The value of x is 5. Angle one and four are vertical. You can do this by writing 7x = 3x + 20. Isolate the variable by moving 3x to the other side. If you do this, 3x becomes negative, and you end up with 7x-3x = 20 --> 4x = 20.
x=5.
FrozenT [24]3 years ago
4 0
m\angle 1=m\angle4\\\\therefore:\\\\7x=3x+20\ \ \ |-3x\\\\4x=20\ \ \ |:4\\\\x=5

Answer: 5

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Jose unlocks his cellphone by placing his right thumb on a square of 1 centimeter by 1 centimeter at the center of the screen. U
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Step-by-step explanation:

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4 0
3 years ago
Can someone please help me with this (make sure it’s right)
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Step-by-step explanation:

\tan \angle A =  \frac{3}{6}  \\  \\  \therefore \:  \tan \angle A =  0.5 \\  \\ \therefore \:  \angle A =  { \tan}^{ - 1}  0.5 \\  \\  \therefore \:  \angle A =  { \tan}^{ - 1}  0.5 \\  \\ \therefore \:  \angle A =  { \tan}^{ - 1}  tan(26.565051177 \degree) \\  \\ \therefore \:  \angle A  = 26.57 \degree

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ddd [48]

The formula for distance is equal to:

d = v * t

where d is distance, v is velocity or speed, and t is time

 

Since the distance travelled by the two airplane is similar, therefore we can create the initial equation:

 

v1 * t1 = v2 * t2

 

We know that v1 = 496, and v2 = 558 so:

 

496 t1 = 558 t2

or

x = 558 t2 / 496

 

We also know that airplane 1 travelled 30 minutes (0.5 hours) earlier than airplane 2, therefore:

 

x = t2 + 0.5

 

Hence,

496 (t2 + 0.5) = 558 t2

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x = 4.5 hours

 

 

So the equation is:

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And the first plane travelled:

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