Question

In the figure, lines a, b, and c are parallel and m∠4=68° . Drag and drop the correct angle measure for each angle. m∠1 = m∠2 = m∠3 = m∠5 = Lines a b and c are parallel and cut by a transversal. Angles 1 to 5 are labeled. Angle 1 is above line a to the left of the transversal. Angle 2 is below line a to the left of the transversal. Angle 3 is above line b to the right of the transversal. Angle 4 is below line b to the right of the transversal. Angle 5 is below line c to the right of the transversal.

Answer 1

Answer:

Step-by-step explanation:

It is given that lines a, b, and c are parallel and m∠4=68°. Then, from the figure,

∠4=∠5=68° (Corresponding angles)

Now, ∠3+∠4=180° (Linear pair)

⇒∠3+68°=180°

⇒∠3=112°

As, ∠2 and ∠3 forms the alternate interior angle pair, thus ∠2=∠3=112°.

And, ∠1+∠2=180° (Linear pair)

⇒∠1+112°=180°

⇒∠1=68°.

Thus, ∠1=68°, ∠2=112°, ∠3=112°,∠4=68°and ∠5=68°.

Answer 2

The complete question in the attached figure

we have that
m∠4=68°

we know that
m∠4 and m∠3 are supplementary angles
so
m∠3=180-m∠4----- m∠3=180-68------> m∠3=112°

m∠3 = m∠2 --------> by alternate interior angles
so
m∠2=112°

m∠1 = m∠4 --------> by alternate exterior angles
so
m∠1=68°

m∠5 = m∠4---------> by corresponding angles
so
m∠5=68°

the answers are
m∠1=68°
m∠2=112
m∠3=112°
m∠5=68°