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3 years ago

15

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1 answer:

fgiga [73]3 years ago

6 0

The question is:

19. if g(x) = 3 + x + e^x, find the inverse function of g (4).

Solution:

1) Put the equation as y = 3 + x + e^x

2) Solve for x = > x + e^x = y - 3

3) switch x and y => y + e^y = x - 3

4) y is the inverse

5) find y for the value requested (x = 4)

=> y + e^y = 4 - 3

=> y + e^y = 1

the solution is y = 0 because 0 + e^0 = 0 + 1 = 1.

Answer: 0.

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What is the surface area of a sphere with radius 2

Gelneren [198K]

Answer:

A

Step-by-step explanation:

The surface area (A) of a sphere is calculated as

A = 4πr² ← r is the radius

here r = 2, hence

A = 4π × 2² = 4π × 4 = 16π units² → A

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3 years ago

Point B is the midpoint of AC, and point C is the midpoint of AD. If CD=12, what is AB?

Sliva [168]

Answer: AB = 6

Step-by-step explanation:

If CD = 12 , AC also = 12

B is the midpoint of AC so one side = 6

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3 years ago

An arithmetic sequence has a1 = 22 and a8 = 43. Find a15.

brilliants [131]

The 15th term of the arithmetic sequence $a_{15} = 64$

Option B is correct

The nth term of an arithmetic sequence is given as:

$a_{n} = a + (n - 1)d$

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$a_8 = a+(8 - 1)d\\a_8 = a + 7d$

Since $a_8 = 43$

$43 = 22 + 7d\\7d = 43 - 22\\7d = 21\\d = \frac{21}{7}\\d = 3$

The common difference, d = 3

$a_{15}= a + (15-1)d\\a_{15} = a + 14d\\a_{15} = 22 + 14(3)\\a_{15} = 22 + 42\\a_{15} = 64$

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2 years ago

Which ruler gives the most precise METRIC measurement?

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3 years ago

Read 2 more answers

1. A weighted coin is biased so that a head is twice as likely to occur as a tail. If the coin is tossed 4 times, what is the pr

ohaa [14]

Answer:

80/81

Step-by-step explanation:

If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.

The probability of getting at least 1 head involves 4 scenarios:

1) 1 Head and 3 Tails

2) 2 Heads and 2 Tails

3) 3 Heads and 1 Tail

4) 4 Heads

Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:

P(at least one head) + P(no heads) = 1

Then, P(at least one head) = 1 - P(no heads)

The probability of 4 tails is:

P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81

Then, P(at least one head) = 1 - 1/81=80/81

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3 years ago