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2 years ago

Point B is the midpoint of AC, and point C is the midpoint of AD. If CD=12, what is AB?

Mathematics

1 answer:

Sliva [168]2 years ago

4 0

Answer: AB = 6

Step-by-step explanation:

If CD = 12 , AC also = 12

B is the midpoint of AC so one side = 6

AB is one side of AC , so AB = 6

I am not a professional, I am simply using prior knowledge!

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Given the Arithmetic sequence A1,A2,A3,A4A1,A2,A3,A4

Bad White [126]

The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59

This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.

The n-th term is
$a_{n}=a_{1}+(n-1)d$
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
= 29 + 320
= 349

Answer: a₃₃ = 349

7 0

2 years ago

What would the measure of DEC be

IceJOKER [234]

So if <AED =100 degrees result <BEC = 100 degrees too and 360-200=160
so 160/2 = 80 what mean that angle DEC=80 degrees

hope helped

3 0

3 years ago

Don’t understand please help

Mazyrski [523]

A is ur answer trust me

7 0

2 years ago

If 2 over 5 tons of concrete covers 5 over 6 of a wall, how many tons of concrete are required to cover the entire wall?

Dominik [7]

Answer:

A. 12.25 tons

Step-by-step explanation:

We will let x represent the amount required to cover the entire wall.

We can divided 2/5 by 5/6 to solve for x

2/5 divided by 5/6=x

When you divide by a fraction, you can always multiply by the reciprocal (flipped number).

Our new equation is:

2/5·6/5=12/25

8 0

1 year ago

Find all solutions to the following system of equations -y²+6y+x-9=0 ; 6y=x+27.Illustrate with a graph.

Dimas [21]

Answer:

The solution to the system is the pair (9, 6)

Step-by-step explanation:

Hi!

First, let´s write the system of equations:

-y² + 6y + x -9 = 0

6y = x +27

The solutions of the system are the pairs (x, y) that satisfy both equations.

Let´s take the second equation and solve it for x:

6y = x +27

Subtract 27 from both sides of the equation

6y - 27 = x

Now, we can replace x in the first equation and solve it for y:

-y² + 6y + x -9 = 0

-y² + 6y + 6y - 27 -9 = 0

-y² + 12y - 36 = 0

Notice that -y² + 12y - 36 = -(y - 6)², then:

-(y - 6)² = 0

y - 6 = 0

y = 6

(alternatively you can solve the quadratic equation using the quadratic formula).

Now let´s find the value of x:

x = 6y -27

x = 6·6 -27

x = 9

The solution to the system is the pair (9, 6)

Please see the attached figure. The point where the curves intersect is the solution to the system.

6 0

3 years ago