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Nana76 [90]
3 years ago
10

A new car that sells for $18.000 depreciates at a rate of 25% per year. Find the value of the car after 4 years ?

Mathematics
1 answer:
Rom4ik [11]3 years ago
4 0

Answer:

After 4 years, the value of the car would be of $5695.31.

Step-by-step explanation:

The formula for compound interest works perfectly in this case:

a = p {(1 +  \frac{r}{n} )}^{nt}

As in this case the repetitions per annum are just 1 (yearly), we can ignore the n.

Replacing variables with our values, a yields the depreciated value:

a = 18000 {(1 - 0.25)}^{4}  \\ a = 18000 {(0.75)}^{4}  \\ a = 18000(0.31640625) \\ a = 5,695.3125 = 5695.31

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Question 22 A city has a population of people. Suppose that each year the population grows by . What will the population be afte
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Answer:

911,690.

Step-by-step explanation:

Please consider the complete question.

A city has a population of 390,000 people. Suppose that each year the population grows by 6.75%. What will the population be after 13 years? Round your answer the nearest whole number.

We will use exponential growth formula to solve our given problem.

y=a\cdot (1+r)^x, where,

y = Final value,

a = Initial value,

r = Growth rate in decimal form,

6.75\%=\frac{6.75}{100}=0.0675

y=390,000\cdot (1+0.0675)^x

y=390,000\cdot (1.0675)^x

To find the population after 13 years, we will substitute x=13 in population growth equation as:

y=390,000\cdot (1.0675)^{13}

y=390,000\cdot 2.3376661492982871

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Upon rounding to nearest whole number, we will get:

y\approx 911,690

Therefore, the population of the city after 13 years would be 911,690.

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