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Yanka [14]
3 years ago
11

every moth ms thomas pays her car loan through automatic payments withdraws fro her savings account she pays the same amount on

her car loan each month at the end of the year her savings account balance saved by -$2,931 from payments made on her car loan what is the change in ms Thomas savings account balance each month due to her car payment?
Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0
I don't know if this helps or not but she pays $244.25 each month.
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NENU
Eddi Din [679]

Answer:

22

Step-by-step explanation:

First arrange the given data in ascending order

17 17 17 18 20 21 21 22 22 22 22 22 22 22.5

The median is the middlemost value, so the median is 22

3 0
3 years ago
When solving this system by elimination, which variable is the most convenient to eliminate,
kobusy [5.1K]

Answer:

Y is the appropriate variable and the most easiest and convenient to eliminate

name 2x + y = 7 as equation i

and 3/2 x - y = 7/2 as equation ii

then add equation i and ii together

(3/2 + 2) x + y - y = (7 + 7/2)

(7/2) x = (21/2)

x = 3

then put in x = 3 in equation i

4 + y = 7

x = 7 - 4

x = 3

Therefore x = 3 and y = 3

4 0
3 years ago
Which one of the following is an equation?<br> O 3m + 2<br> 3m<br> 2<br> 3m +2 = 11
AVprozaik [17]

Answer:

3m+2=11

Step-by-step explanation:

Because equation is joined with equal sign

5 0
3 years ago
Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

7 0
2 years ago
Dylan has 1,024 in credit card debt. The credit card has an APR of 15% and is compounded monthly. If he pays 300 per month, how
daser333 [38]

Answer:

2.1314 Months.

Step-by-step explanation:

7 0
3 years ago
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