Ok since your given two points of (-5,2) and origin which is always (0,0) you can find the slope with this formula of y2-y1/x2-x1 plug them in the formula and you should get 0-2/0-5 which is equal to -2/-5 or 2/5 negative signs cancel out now you found your slope but remember the promblem was asking for perpendicular slope to get this you simply flip or reciprocate the slope and take take the opposite sign in our case the slope is 2/5 but the perpendicular version is -5/2 hope this helps.
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Answer:</h2>

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Step-by-step explanation:</h2>








<em>I hope this helps you</em>
<em>:)</em>
<span>Highest point = 1406.25
Number of seconds = 9.375
We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375
So let's calculate the height at t = 9.375.
y = -16t^2 + 300t
y = -16(9.375)^2 + 300(9.375)
y = -16(87.890625) + 300(9.375)
y = -1406.25 + 2812.5
y = 1406.25
So the highest point will be 1406.25 after 9.375 seconds.
Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.'
y = -16t^2 + 300t
y = -16(9.375 + e)^2 + 300(9.375 + e)
y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e)
y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e
y = 1406.25 - 16e^2
Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
Answer:
I am not positive but I believe X = 6 so the total, if you add it up, would be 180
Step-by-step explanation:
64 + 110 = 174 + 6 = 180
Hope this helps
Answer:

Step-by-step explanation:
Diameter = 22 units
Radius = 11 units
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)

![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>