2 years ago

Can anyone please help

Mathematics

1 answer:

mixer [17]2 years ago

4 0

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Sholpan [36]

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$x + 3y -z - 3 = 0$

Step-by-step explanation:

We have to find the equation of plane that is parallel to the vectors

$\langle 3,0,3\rangle, \langle0,1,3\rangle$

The plane also passes through the point (2,0,-1).

Hence, the equation of plane s given by:

$\displaystyle\left[\begin{array}{ccc}x-2&y-0&z+1\\3&0&3\\0&1&3\end{array}\right]\\\\=(x-2)(0-3) - (y-0)(9-0) + (z+1)(3-0)\\=-3(x-2)-9y+3(z+1)\\\Rightarrow -3x + 6 - 9y + 3z + 3 = 0\\\Rightarrow 3x + 9y -3z -9 = 0\\\Rightarrow x + 3y -z - 3 = 0$

It is the required equation of plane.

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3 years ago