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frez [133]
3 years ago
7

BRO'S HELP ME!! If you tripled the slant height and radius of a cone, what would be the formula to find the modified surface are

a?
Answer: SA=? πrl + ? πr^2
Mathematics
1 answer:
suter [353]3 years ago
5 0
<span>If you tripled the slant height and radius of a cone, the formula to find the modified surface area would be 6 and 6. I am hoping that this answer has satisfied your query about and it will be able to help you, and feel free to ask another question if you’d like.</span>
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Find the slope of the line that passes through the pair of points. ​(negative 44.29−44.29​,4.84.8​) and ​(5.295.29​,3.53.5​)
Damm [24]
1.7602899999999995x + 49.138y = 182.23671592000002

6 0
3 years ago
I'll. ark brainlyest and give a lot of points for answering this right ​
valina [46]

Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

\displaystyle S' ( 3,2)

Step-by-step explanation:

we current vertices of the given triangle

  • \displaystyle T( - 2,4)
  • \displaystyle U( - 1,1)
  • \displaystyle S ( - 3,2)

remember that,

\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \:  over \: y - axis}( -  x,y)

so we obtain:

\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \:  over \: y - axis}T'(  2,4)

\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \:  over \: y - axis}U' ( 1,1)

\rm\displaystyle S( - 3,2) \xrightarrow{ \rm reflection \:  over \: y - axis}S'( 3,2)

6 0
2 years ago
I really need help im confuzzled​
azamat

Answer: same

Step-by-step explanation:

6 0
3 years ago
Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

So

X(t) = 43.45t

After 2 seconds the horizontal distance reached by the ball is:

X (2) = 43.45(2)\\\\X (2) = 87\ ft

Finally the vector position P is:

P = 87\^x + 75\^y ft

6 0
3 years ago
Marshall and Peter went to lunch at a cafe. They ordered a spinach salad for $4.15, a tuna sandwich for $6.35, and 2 glasses of
garri49 [273]

Answer:

$1.05

Step-by-step explanation:

The amount of money they should pay is 4.15+6.35+2*1.1+1.25 = $13.95

The change is 15-13.95=$1.05

8 0
3 years ago
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