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german
3 years ago
6

the matrix below represents the distance in miles between three cities. A row label represents the city traveled from. A column

label represents a city traveled to. what is the round trip distance in miles from city 1 to city 3

Mathematics
2 answers:
Lyrx [107]3 years ago
6 0

Answer:

The round trip distance in miles from city 1 to city 3 is 15. Therefore the correct option is 1.

Step-by-step explanation:

It is given that the matrix below represents the distance in miles between three cities. A row label represents the city traveled from. A column label represents a city traveled to.

\begin{bmatrix}0 & 5 & 15\\ 5 & 0 & 35\\ 15 & 35 &0 \end{bmatrix}

Here first element of first row represents the distance in miles from city 1 to city 1.

C_1\Rightarrow C_1=0

Second element of first row represents the distance in miles from city 1 to city 2.

C_1\Rightarrow C_2=5

Third element of first row represents the distance in miles from city 1 to city 3.

C_1\Rightarrow C_3=15

The round trip distance in miles from city 1 to city 3 is 15. Therefore the correct option is 1.

REY [17]3 years ago
4 0

Answer:

\large\boxed{30}

Step-by-step explanation:

.\qquad\ \ \begin{array}{ccc}c_1&c_2&c_3\end{array}\\\begin{array}{ccc}c_1\\c_2\\c_3\end{array}\left[\begin{array}{ccc}0&5&15\\5&0&35\\15&35&0\end{array}\right]\\\\\\Look\ at\ the\ picture.\\\\\text{from city1 to city3 (red lines) - 15 miles}\\\\\text{from city1 to city3 (blue lines) - 15 miles}\\\\15\ miles+15\ miles=30\ miles

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Answer:

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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\bar X=98.9 represent the sample mean for the sample  

\mu population mean (variable of interest)

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Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

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Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that t_{\alpha/2}=2.62

Now we have everything in order to replace into formula (1):

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98.9+2.62\frac{0.65}{\sqrt{103}}=99.07    

So on this case the 99% confidence interval would be given by (98.73;99.07)    

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