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krok68 [10]
3 years ago
10

What should a password policy contain to reduce a hackers ability to crack the passwords?

Computers and Technology
1 answer:
Aleksandr-060686 [28]3 years ago
4 0

Creating a strong password<span> is an important part of protecting your account.  T</span>he following character sets should all be included in every password:

uppercase letters such as A, B, C;                                                                    lowercase letters such as a, b,c;                                                                        numerals such as 1, 2, 3;                                                                              special characters such as $, ?, &;                                                                    alt characters such as µ, £, Æ. (Cliff) 

<span>Misspell words or create acronyms;
</span><span>Use punctuation characters to separate words or acronyms;
</span><span>Change passwords every 6 to 12 months;
</span>Use variable-length passwords;<span> 
</span><span>Don’t rely completely on similar-looking characters, such as 3 instead of <span>E, 5 </span>instead of S,or <span>! </span>instead of 1.</span> 
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Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur
sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

   for ip in range(octet_start, octet_end):

       forth_octet = forth_octet + 1

       if forth_octet > 255:

           forth_octet = (forth_octet % 255) - 1

           third_octet = third_octet + 1

           if third_octet > 255:

               third_octet = (third_octet % 255) - 1

               second_octet = second_octet + 1

               if second_octet > 255:

                   second_octet = (second_octet % 255) - 1

                   first_octet = first_octet + 1

                   if first_octet > 255:

                       print("No more available IP!")

                       break

       print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

   print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0
3 years ago
The smallest unit of time in music called?
zmey [24]

Answer:

Ready to help ☺️

Explanation:

A <em>tatum</em> is a feature of music that has been defined as<u> the smallest time interval</u> between notes in a rhythmic phrase.

7 0
3 years ago
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What was named the worst game ever?
Schach [20]

Answer:

Fortnight

Explanation:

7 0
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) Which of the following operating system designs allows direct intercommunication between every component, making the system hi
artcher [175]

Answer:

The answer to this question is option (a).

Explanation:

In this question is option (a) is the correct answer because the distributed Os is an operating system that collects separated computational nodes. It manages jobs that are maintained by many CPUs. In this operating system, each node holds a particular software that is a batch of the global aggregate operating system.

So the correct answer to this question is option(a).

3 0
2 years ago
This program outputs a downwards facing arrow composed of a rectangle and a right triangle. The arrow dimensions are defined by
stira [4]

Answer:

Here is the C program:

#include <stdio.h>  //to use input output functions

int main(void) {   //start of main function

 int arrowBaseHeight = 0;  //stores value for arrow base height

int  arrowBaseWidth = 0;  //stores value for arrow base width

 int arrowHeadWidth = 0 ;  //stores value for arrow head width

 int i, j;  //to traverse through the rows and columns

 printf("Enter arrow base height:\n");  //prompts user to enter arrow base height value

 scanf("%d", &arrowBaseHeight);  //reads input value of arrow base height

 printf("Enter arrow base width:\n");  //prompts user to enter arrow base width value

 scanf("%d", &arrowBaseWidth);  //reads input value of arrow base width

 while (arrowHeadWidth <= arrowBaseWidth)  {   //iterates as long as the value of arrowHeadWidth is less than or equals to the value of arrowBaseWidth  

     printf("Enter arrow head width:\n");   //prompts user to enter arrow head width value

     scanf("%d", &arrowHeadWidth);   //reads input value of arrow head width

     printf("\n"); }

 for (i = 0; i < arrowBaseHeight; i++)    {   //iterates through rows

     for (j = 0; j < arrowBaseWidth; j++)  {   //iterates through columns

         printf("*");       }   //prints asterisks

     printf("\n");   }   //prints a new line

 for (i = arrowHeadWidth; i > 0; i--)    {   //loop for input length

     for (j = i; j > 0; j--)        {   //iterates for triangle ( to make arrow head)

         printf("*");       }   //prints asterisks

     printf("\n");   }  } //prints new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.  

The loop is used to output an arrow base of height arrowBaseHeight.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head.  

The screenshot of output is attached.

8 0
2 years ago
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