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sertanlavr [38]
3 years ago
7

This reddish layer of the atmosphere of the Sun is not normally visible, but the ________________ may be seen briefly during a t

otal Solar eclipse and using ultraviolet telescopes
Physics
1 answer:
kupik [55]3 years ago
8 0

Answer:

Chromosphere

Explanation:

The Chromosphere is one of the important internal layers of the sun, which lies above the layer of Photosphere. The Chromosphere has a thickness of about 3 to 5 km having a very high temperature, ranging from about 5000 to 20,000°C. Due to this extreme temperature and continuous nuclear fusion process that takes place at the core of the sun, there forms the reddish colored layer, which is usually not visible but can be observed during the time of a total solar eclipse, by the use of an ultraviolet telescope.

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What is the height in meters of a person who is 6 ft 1.0 in. Tall?
Aliun [14]

Answer:1.85 m

Explanation:

3 0
3 years ago
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4. Calculate the kinetic energy of a 4.7 kg object moving at a speed of 7 m/s. SHOW YOUR WORK
SashulF [63]

Answer:

\boxed {\boxed {\sf 115.15 \ J}}

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated with the following formula.

E_K= \frac{1}{2} mv^2

The mass of the object is 4.7 kilograms. The velocity of the object is 7 meters per second.

  • m= 4.7 kg
  • v= 7 m/s

Substitute the values into the formula.

E_K= \frac{1}{2} (4.7 \ kg)(7 \ m/s)^2

Solve the exponent.

  • (7 m/s)²= 7 m/s * 7 m/s = 49 m²/s²

E_K= \frac{1}{2} (4.7 \ kg)(49 \ m^2/s^2)

Multiply the numbers together.

E_K = 2.35 \ kg * 49 \ m^2/s^2

E_K= 115.15 \ kg*m^2/s^2

Convert the units. 1 kilogram square meter per square second is equal to 1 Joule.

E_K= 115.15 \ J

The object has <u>115.15 Joules</u> of kinetic energy.

3 0
2 years ago
Read 2 more answers
A golf ball starts with a speed of 2 m/s and slows at a constant rate of 0.5 m/s2, what is its velocity after 2 s?​
jeka57 [31]

Answer:

3m/s

Explanation:

Given parameters:

Initial speed  = 2m/s

Acceleration  = 0.5m/s²

Time  = 2s

Unknown:

Final speed  = ?

Solution:

To solve this problem, we apply the right motion equation;

     V  = U + at

V is the final speed

U is the initial speed

a is the acceleration

t is the time

      V = 2  + (2 x 0.5)

      V = 2 + 1

      V = 3m/s

8 0
3 years ago
Why do electrons flow around a circuit when the circuit is complete?
Alik [6]
Metals contain free moving delocalized electrons. When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.
7 0
3 years ago
Consider six proposed properties of electromagnetic radiation: wave speeds of 3.00×108 km/s3.00×108 km/s and 3.00×108m/s3.00×108
-Dominant- [34]

Answer:

1) Speed ​​of light (c)       visible, X-rays

2) λ = 0.221 nm                         X-rays

3) λ = 673 nm               Visible

4) .f = 2.39 10¹⁸ Hz                   X-rays

5) .f = 4.85 10¹⁴ Hz        Visible

Explanation:

Electromagnetic radiation has several characteristics

The speed of the wave regardless of its wavelength or frequency is

        c = 3 10⁸ m / s²

There is a relationship with speed

       c = λ f

The speed c is for all waves (x-rays, visible)

Visible light has a wavelength between 400 nm to 700 nm,

X-ray light corresponds to wavelengths less than 10 nm

Light gamma rays for wavelength less than 0.1 nm

Let's look for the frequencies for the two ranges

Visible

      f = c /λ

       f = 3 10⁸/400 10⁻⁹ = 7.5 10¹⁴ Hz

       f = 3 10⁸ (/ 700 10⁻⁹ = 4.29 10¹⁴ Hz

Visible range of the order of 10¹⁴ Hz

X-rays

       f = 3 10⁸/10 10⁻⁹ = 3 10¹⁶ Hz

       f = 3 10⁸ / 0.1 10⁻⁹ = 3 10¹⁸ Hz

 

X-ray higher frequency 10¹⁶ Hz

1) Speed ​​of light (c)       visible, X-rays

2) λ = 0.221 nm                         X-rays

3) λ = 673 nm               Visible

4) .f = 2.39 10¹⁸ Hz                   X-rays

5) .f = 4.85 10¹⁴ Hz        Visible

7 0
4 years ago
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