A pressure is applied to 2L of water. The volume is observed to decrease to 18.7 L. Calculate the applied pressure.
1 answer:
Answer:
Applied pressure is 1.08 10⁵ Pa
Explanation:
This exercise is a direct application of Boyle's law, which is the application of the state equation for the case of constant temperature.
PV = nR T
If T is constant, we write the expression for any two points
Po Vo = p1V1
From the statement the initial pressure is the atmospheric pressure 1.01 10⁵ Pa, so we clear and calculate
1 Pa = 1 N / m2
P1 = Po Vo / V1
P1 = 1.01 10⁵ 20/18.7
P1 = 1.08 10⁵ Pa
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Answer:
40KJ
Explanation:
m=200g
V=20m/s
Ek=?
Ek=(m*V²)/2
Ek=(200*20²)/2
Ek=(200*400)/2
Ek=80 000/2
Ek=40 000 J =40KJ
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