The correct answer for this question is this one: C) 2.5s. T<span>he period and frequency of a water wave if 4.0 complete waves pass a fixed point in 10 seconds is that 2.5 s
</span>
Here are the following choices:
<span>A) 0.25s
B) 0.40s
C) 2.5s
D) 4.0s</span>
Answer:
Intensity of beam 18 feet below the surface is about 0.02%
Explanation:
Using Lambert's law
Let dI / dt = kI, where k is a proportionality constant, I is intensity of incident light and t is thickness of the medium
then dI / I = kdt
taking log,
ln(I) = kt + ln C
I = Ce^kt
t=0=>I=I(0)=>C=I(0)
I = I(0)e^kt
t=3 & I=0.25I(0)=>0.25=e^3k
k = ln(0.25)/3
k = -1.386/3
k = -0.4621
I = I(0)e^(-0.4621t)
I(18) = I(0)e^(-0.4621*18)
I(18) = 0.00024413I(0)
Intensity of beam 18 feet below the surface is about 0.2%
<u>Answer:</u>
For 1: The correct option is Option C.
For 3: The final velocity of the opponent is 1m/s
<u>Explanation: </u>
During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:
...(1)
where,
are the mass, initial velocity and final velocity of first object
are the mass, initial velocity and final velocity of second object
<u>For 1:</u>
We are Given:

Putting values in equation 1, we get:

Hence, the correct answer is Option C.
Impulse is defined as the product of force applied on an object and time taken by the object.
Mathematically,

where,
F = force applied on the object
t = time taken
J = impulse on that object
Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.
Hence, the impulse remains the same.
Let the speed in right direction be positive and left direction be negative.
We are Given:

Putting values in equation 1, we get:

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.
Answer:
the maximum mass suspended to the styrofoam sphere is m = 113.1 kg
Explanation:
The weight due to suspended mass is counterbalanced by the buoyancy force on the sphere
So here we will say

as we know that the maximum buoyancy force that will act on the styrofoam sphere is given as




now from above equation we have


so the maximum mass suspended to the styrofoam sphere is m = 113.1 kg