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Karolina [17]
3 years ago
10

The electrostatic force between two charged metal spheres is 2N. If the charge on each sphere is doubled, what is the new force

between the spheres?
Question 2 options:
A. 2N
B. 4N
C. 1N
D. 8
Physics
1 answer:
Aleks [24]3 years ago
4 0

Answer:

8 N

Explanation:

The force between two charges is given by :

F=\dfrac{kq_1q_2}{d^2}

Where

k is electrostatic constant

d is the distance between two charges

It means,

F\propto \dfrac{1}{d^2}

When the distance is d, the force is 2 N. If the charge on each sphere is doubled, q₁' = q₂' = 2q₁ = 2q₂. New force will becomes:

F'=\dfrac{kq_1'q_2'}{d^2}\\\\F'=\dfrac{k2q_1\times 2q_2}{d^2}\\\\F'=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4\times 2\\\\F'=8\ N

So, the new force becomes 8N. Hence, the correct option is (d).

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Here are the following choices:
<span>A) 0.25s 
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7 0
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When a vertical beam of light passes through a transparent medium, the rate at which its intensity I decreases is proportional t
antoniya [11.8K]

Answer:

Intensity of beam 18 feet below the surface is about 0.02%

Explanation:

Using Lambert's law

Let dI / dt = kI, where k is a proportionality constant, I is intensity of incident light and t is thickness of the medium

then dI / I = kdt

taking log,

ln(I) = kt + ln C

I = Ce^kt

t=0=>I=I(0)=>C=I(0)

I = I(0)e^kt

t=3 & I=0.25I(0)=>0.25=e^3k

k = ln(0.25)/3

k = -1.386/3

k = -0.4621

I = I(0)e^(-0.4621t)

I(18) = I(0)e^(-0.4621*18)

I(18) = 0.00024413I(0)

Intensity of beam 18 feet below the surface is about 0.2%

3 0
3 years ago
When energy decreases, particle motion:<br> A. stops<br> B. increases<br> C. decreases
DaniilM [7]
C. decreases here you go
7 0
3 years ago
Read 2 more answers
1.
Gwar [14]

<u>Answer:</u>

For 1: The correct option is Option C.

For 3: The final velocity of the opponent is 1m/s

<u>Explanation: </u>

During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:

m_1u_1+m_2u_2=m_1v_1+m_2v_2      ...(1)

where,

m_1,u_1\text{ and }v_1 are the mass, initial velocity and final velocity of first object

m_2,u_2\text{ and }v_2 are the mass, initial velocity and final velocity of second object

<u>For 1:</u>

We are Given:

m_1=150g=0.15kg\\u_1=?m/s\\v_1=0.85m/s\\m_2=3500g=3.5kg\\u_2=0m/s\\v_2=0.85m/s

Putting values in equation 1, we get:

(0.15\times u_1)+(3.5\times 0)=(3.5+0.15)\times 0.85\\\\u_1=20.683\approx 21m/s

Hence, the correct answer is Option C.

  • <u>For 2: </u>

Impulse is defined as the product of force applied on an object and time taken by the object.

Mathematically,

J=F\times t

where,

F = force applied on the object

t = time taken

J = impulse on that object

Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.

Hence, the impulse remains the same.

  • <u>For 3:</u>

Let the speed in right direction be positive and left direction be negative.

We are Given:

m_1=240kg\\u_1=0m/s\\v_1=-1m/s\\m_2=80kg\\u_2=-2m/s\\v_2=?m/s

Putting values in equation 1, we get:

(240\times 0)+(80\times (-2))=(240\times (-1))+(80\times v_2)\\\\v_2=1m/s

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.

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3 years ago
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I am Lyosha [343]

Answer:

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Explanation:

The weight due to suspended mass is counterbalanced by the buoyancy force on the sphere

So here we will say

F_b = mg

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F_b = \rho V g

F_b = (1000)(\frac{4}{3}\pi r^3)g

F_b = (1000)(\frac{4}{3}\pi(0.30)^3)(9.81)

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now from above equation we have

113.1 \times 9.81 = m\times 9.81

m = 113.1 kg

so the maximum mass suspended to the styrofoam sphere is m = 113.1 kg

3 0
3 years ago
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