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emmasim [6.3K]
3 years ago
6

Why do electrons flow around a circuit when the circuit is complete?

Physics
1 answer:
Alik [6]3 years ago
7 0
Metals contain free moving delocalized electrons. When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.
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(1 point) Which of the following statements are true?A.The equation Ax=b is referred to as a vector equation.B.If the augmented
Anvisha [2.4K]

Answer:

A. False

B. False

C. True

D. True

E. True

F. True

Explanation:

A. The equation Ax=b is referred to as a matrix equation and not vector equation.

B. If the augmented matrix [ A b ] has a pivot position in every​ row then equation Ax=b may or may not be consistent. It is inconsistent if [A b] has a pivot in the last column b and it is consistent if the matrix A has a pivot in every row.

C. In the product of Ax also called the dot product the first entry is a sum of products. For example the the product of Ax where A has [a11 a12 a13] in the first entry of each column and the corresponding entries in x are [x1 x2 x3] then the first entry in the product is the sum of products i.e.  a11x1 + a12x2 +a13x3

D. If the columns of mxn matrix A span R^m, this states that every possible vector b in R^m is a linear combination of the columns which makes the equation consistent. So the equation Ax=b has at least one solution for each b in R^m.

E. It is stated that a vector equation x1a1 + x2a2 + x3a3 + ... + xnan = b has the same solution set as that of the linear system with augmented matrix [a1 a2 ... an b]. So the solution set of linear system whose augmented matrix is [a1 a2 a3 b] is the same as solution set of Ax=b if A=[a1 a2 a3]  and b can be produced by linear combination of a1 a2 a3 iff the solution of linear system corresponding to [a1 a2 a3 b] takes place.

F.  It is true because lets say b is a vector in R^m which is not in the span of  the columns. b cannot be obtained for some x which belongs to R^m as b = Ax. So Ax=b is inconsistent for some b in R^m and has no solution.

8 0
3 years ago
Question 3 (1 point)
FrozenT [24]

The force of friction is equal to the pushing force, and the acceleration is zero

Explanation:

In this problem, we are pushing a piano along the floor, in the horizontal direction.

There are 2 forces acting in the horizontal direction on the piano:

  • The applied force, F_a, acting forward
  • The force of friction, F_f, acting backward

Therefore, the net force in the horizontal direction is

\sum F = F_a - F_f

According to Newton's second law, the net force is equal to the product between the piano's mass (m) and its acceleration:

\sum F = ma

Combining the two equations,

F_a - F_f = ma

However, we are also told that the piano moves at constant speed, therefore the acceleration is zero:

a=0

And so,

F_a - F_f = 0\\F_f = F_a

which means that the force of friction is equal to the applied force.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

3 0
3 years ago
A person with a mass of 72 kg is riding a bicycle is accelerating at a rate of 5m/s on a horizontal surface. What is the weight
nikklg [1K]

Answer:

w = 706.32 [N]

Explanation:

The force due to gravitational acceleration can be calculated by means of the product of mass by gravitational acceleration.

w = m*g

where:

w = weight [N] (units of Newtons)

m = mass = 72 [kg]

g = gravity acceleration = 9.81 [m/s²]

Then we have:

w = 72*9.81\\w = 706.32 [N]

7 0
3 years ago
How long does it take for the Earth to make a complete revolution around the sun?
timurjin [86]

365 days so a year basically

4 0
3 years ago
Read 2 more answers
A copper wire 12 cm long and a mass of 16 g is in a magnetic field of 1.2 T oriented perpendicular to the wire. What current wou
Ugo [173]

Answer:

Current, I = 1.08 A

Explanation:

Given that,

Length of the copper wire, l = 12 cm = 0.12 m

Mass of the wire, m = 16 g = 0.016 kg

Magnetic field, B = 1.2 T

The magnetic field is oriented perpendicular to the wire. We need to find the current in the wire.

Magnetic force, F = BIL

Force of gravity, F' = mg

F' = F

BIL=mg

I=\dfrac{mg}{BL}

I=\dfrac{0.016\times 9.8}{1.2\times 0.12}

I = 1.08 A

So, the current through the wire is 1.08 A. Hence, this is the required solution.

8 0
4 years ago
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