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GaryK [48]
3 years ago
7

consider the following system of equations 2x+3y=45 x+y=10 what is the x value of the solution for this system

Mathematics
2 answers:
mixer [17]3 years ago
7 0
X + y = 10.....y = 10 - x....so we sub in 10 - x for y in the other equation

2x + 3y = 45
2x + 3(10 - x) = 45
2x + 30 - 3x = 45
2x - 3x = 45 - 30
-x = 15
x = -15 <===
sesenic [268]3 years ago
4 0

Answer:

value of x = -15

Step-by-step explanation:

Given the system of equation:

2x+3y = 45              .....[1]

x+y = 10                  ......[2]

Multiply equation [2] with 3 we have;

3x+3y =30          ......[3]

Subtract equation [3] from [1] to eliminate y and solve for x;

2x+3y-3x-3y = 45-30

Combine like terms;

-x =15

Divide both side by -1 we have;

x = -15

Therefore, the value of x of the solution for the given system is, -15

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