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DochEvi [55]
4 years ago
9

In your own words, write a definition for the word:Base:

Mathematics
1 answer:
Luba_88 [7]4 years ago
8 0
The main part of something or the bottom of an object.
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X^3-3x^2=0<br> Write in quadratic form
Reptile [31]

Answer:

x=0,3

Step-by-step explanation:

3 0
3 years ago
Tyrone runs 5 mph how far can he travel in two hours and 30 minutes
zaharov [31]

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12.5 miles

Step-by-step explanation:

5x2.5=12.5 miles

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3 years ago
Paul wrote the equation t=2m+40 to represent the temperature, t, in degrees Celsius, after a substance had been heated for m min
Usimov [2.4K]
First you need to fill in the variables with what you already know, so
t=2m+40.
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4 0
3 years ago
At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37
monitta

Answer:

Half-life of the goo is 49.5 minutes

G(t)= 300e^{-0.014t}

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let M_0\,,\,M_f denotes initial and final mass.

M_0=300\,\,grams\,,\,M_f=37.5\,\,grams

According to exponential decay,

\ln \left ( \frac{M_f}{M_0} \right )=-kt

Here, t denotes time and k denotes decay constant.

\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014

So, half-life of the goo in minutes is calculated as follows:

\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes

Half-life of the goo is 49.5 minutes

\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}

So,

G(t)= M_f=M_0e^{-kt}

Put M_0=300\,\,grams\,,\,k=0.014

G(t)= 300e^{-0.014t}

Put t = 32 minutes

G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams

7 0
3 years ago
Enter the slope of the line through the points (-9, -6) and (3,-9). *​
astraxan [27]

Answer:

Step-by-step explanation:

Do you have a number line or grid

7 0
3 years ago
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