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Xelga [282]
3 years ago
11

Why does a perfume bottle burst when placed inside the flame​

Chemistry
2 answers:
madreJ [45]3 years ago
6 0

Answer:

It's because the perfume bottle contains ethyl alcohol.

babymother [125]3 years ago
6 0
It is because perfume has ethyl alcohol
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Write a balanced net ionic equation for the following reaction: SrCl2(aq) + H2CO3(aq) → SrCO3(s) + HCl (aq)
max2010maxim [7]
  We will balance the equation in the following order: metals, amethals, carbon, hydrogen and oxygen (the most common order).
  The metal present in the equation is Sr, which is already balanced (there are 1 on each side of the equation).
  The amethal present in the equation is Cl. There is 2 Cl in the left side and only one in the right side. So, we will multiply the quantity of the molecule that contains Cl by 2. Doing this, we'll obtain:

SrCl_2_{(aq)}+H_2CO_3_{(aq)}\to SrCO_3_{(s)}+2HCl_{(aq)}
 
  Looking at the equation, we can see that it is now fully balanced. Hence, a balanced equation of the reaction is:

SrCl_2_{(aq)}+H_2CO_3_{(aq)}\to SrCO_3_{(s)}+2HCl_{(aq)}
5 0
3 years ago
An indicator is what type of compound?
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3 0
4 years ago
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2. What major alkene product is produced by the dehydration of the following alcohols?
weeeeeb [17]
2-Dimethylcyclohexanol <span>major alkene product is produced by the dehydration of the  alcohols.</span>
4 0
3 years ago
Which statement accurately describes radioactive dating?
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Explanation:

7 1
3 years ago
Name a possible product of this reaction in the presence of ether and AlCl3: methylbenzene + 1-chlorodecane.a. 1-methyl-2-decylb
Vikki [24]

Answer:

None of these

Explanation:

Friedel–Craft reaction is a reaction involves the attachment of substituents to the benzene ring.

Mechanism of the reaction of methylbenzene with 1-chlorodecane in the presence of ether and aluminum chloride :

Step -1 : Generation of stable carbocation.

Aluminium chloride acts as Lewis acid which removes the chloride ion from the alkyl halide forming carbocation. The primary carbocation thus formed gets rearranged to secondary primary carbocation which is more stable due to hyperconjugation.

Step-2: Attack of the ring to the carbocation

The pi electrons of the ring behave as a nucleophile and attacks the carbocation. Since, the group attached on the benzene is methyl (+R effect) , the attack is from the ortho and the para positions. Para product is more stable due to less steric hinderance.

The product formed is shown in mechanism does not mention in any of the options.

So, None of these is the answer

8 0
4 years ago
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