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Anna007 [38]
3 years ago
8

The pressure exerted by a gas in a container depends on what?

Chemistry
1 answer:
lyudmila [28]3 years ago
7 0

Answer:

From gas laws (pressure law and Boyles law), the pressure exerted by a gas depends on Temperature of the gas and volume of the container.

Explanation:

{ \boxed{ \rm{P \:  \alpha  \:  \frac{T}{V} }}}

• P → Pressure exerted by the gas.

• T → Temperature of the gas.

• V → Volume of the container.

• from the expression, pressure exerted by the gas is directly proportional to temperature of the gas and inversely proportional to the volume of the container.

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Which statement best describes comparative and descriptive investigations?
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they both include a question, procedure and conclusion.

Explanation:

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Milk of magnesia is often taken to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 te
Igoryamba

Answer:

8.61 mL of the HCl solution

Explanation:

The reaction that takes place is:

  • 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O

From the given mass of Mg(OH)₂, we can calculate <u>the moles of HCl that are neutralized</u>:

  • 4x10² mg = 400 mg = 0.400g
  • 0.400g Mg(OH)₂ ÷ 58.32g/1mol = 6.859*10⁻³ mol Mg(OH)₂
  • 6.859*10⁻³ mol Mg(OH)₂ * \frac{1molHCl}{1molMg(OH)_{2}} = 3.429x10⁻³ mol HCl

Finally, to calculate the volume of an HCl solution, we need both the moles and the concentration. We can <u>calculate the concentration using the pH value</u>:

  • pH = -log[H⁺]
  • 1.4 =  -log[H⁺]
  • 10^{-1.4} = [H⁺]
  • 0.0398 M = [H⁺] = [HCl]  *Because HCl is a strong acid*

Thus, the volume is:

  • 0.0398 M = 3.429x10⁻³mol HCl / Volume
  • Volume = 8.616x10⁻³ L = 8.62 mL

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4 years ago
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Name a Solid, Liquid, and a Gas. Solid: Liquid: Gas:
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A 5.00 cm^3 sample of gold has a mass of 96.5 g. Calculate the density of gold.
Sholpan [36]

Answer:

\boxed {\boxed {\sf 19.3 \ g/cm^3}}

Explanation:

We are asked to calculate the density of gold. The density of a substance is its mass per unit volume. It is calculated using the following formula.

\rho= \frac{m}{v}

The mass of the sample is 96.5 grams. The volume of the sample is 5.00 cubic centimeters.

  • m= 96.5 g
  • v= 5.00 cm³

Substitute the values into the formula.

\rho= \frac{ 96.5 \ g}{5.00 \ cm^3}

Divide.

\rho= 19.3 \ g/cm^3

The density of gold is <u>19.3 grams per cubic centimeter.</u>

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