Answer: Option (1) is the correct answer.
Explanation:
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
With increase in atomic size of the atom, there will be less force of attraction between the nucleus and the valence electrons of the atom. Hence, with lesser amount of energy the valence electrons can be removed.
When we move across a period then due to increase in force of attraction the size of atom decreases.
Thus, we can conclude that Phosphorus has a higher ionization energy than silicon because the outer orbitals of phosphorus are located closer to the nucleus than the outer orbitals of silicon.
Ionic compounds are formed by a positive ion called cation and a negative ion called anion.
I will show you some examples:
NaCl is formed by the cation Na+ and the anion Cl -
CaF2 is formed by the cation Ca 2+ and the anion F -
Li2O if formd by the cation Li + and the anion O 2-.
To tell that you use the oxidation number of each element. I did it this way
Ca F2 => Ca has oxidation number 2+ and F has oxidation number 1- then the ions have that very same charge number.
There are 84 metal elements
The question is incomplete, the complete question is;
Using the following equation 2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq) how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid
Answer:
355.1 g
Explanation:
The equation of the reaction is;
2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq)
We have been told that H2SO4 is in excess so NaOH is the limiting reactant. Therefore;
Number of moles in 200g of NaOH = 200g/40g/mol = 5 moles
So;
2 moles of NaOH yields 1 mole of Na2SO4
5 moles of NaOH will yield 5 * 1/2 = 2.5 moles of Na2SO4
Molar mass of Na2SO4 = 142.04 g/mol
Mass of Na2SO4= 2.5 moles * 142.04 g/mol = 355.1 g
