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Nata [24]
3 years ago
13

Which are examples of conserving? Choose the two correct answers.

Chemistry
2 answers:
bija089 [108]3 years ago
8 0
C and D. Conserving plastic through the three R’s, and reducing production of new materials by Reusing old ones
SashulF [63]3 years ago
3 0

Answer:

B)

Explanati on:

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How many grams of carbon dioxide are produced from 0.98 mol of Fe3O4?
nexus9112 [7]
Hello

the answer is 43.129310000000004

Have a nice day
4 0
3 years ago
Number of
babymother [125]

Answer:

A) 20

B) 40

C) Ca

D) 10

E) 9

F) F

Explanation:

The MASS NUMBER is the number of protons + the number of neutrons.

The ATOMIC NUMBER is the number of protons.

You can take the MASS NUMBER - ATOMIC NUMBER = NUMBER OF NEUTRONS.

Each element is unique and distinguished by the NUMBER OF PROTONS = ATOMIC NUMBER, ie...the number of protons in its nucleus. You can find the element's name and symbol on the Periodic Table.

8 0
1 year ago
Determine the mass of CO2 gas produced when 8.24 g of NaHCO3 is added to a solution that contains 4.41 g of HCl.
hjlf

The mass of CO₂ gas = 4.312 g

<h3>Further explanation</h3>

Reaction

NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)

Find limiting reactant

mol NaHCO₃

\tt \dfrac{8.24}{84,007 }=0.098

mol HCl

\tt \dfrac{4.41}{36.5}=0.121

Limiting reactant :  NaHCO₃ (smaller)

mol CO₂ = mol NaHCO₃ = 0.098

mass CO₂ :

\tt 0.098\times 44=4.312~g

4 0
2 years ago
Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi
lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

Mass of water ,m= 1kg = 1000 g

Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

q=-1.061^oC(1000 g\times 4.184J/g^oC+4.643 J/^oC )=-4,444.15J=-4.444 kJ

Moles of propane =\frac{1.860 g}{44 g/mol}=0.0422 mol

0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

\frac{4.444 kJ}{0.0422 mol}=105.308 kJ/mol

3 0
3 years ago
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Monica [59]
50% - you have two bb pairs
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